Solve by Factoring 3(2x-4)=6(x-2)

$3 (2 x - 4) = 6 (x - 2)$

Step 1

Subtract $6 (x - 2)$ from both sides of the equation.

$3 (2 x - 4) - 6 (x - 2) = 0$

Step 2

Simplify $3 (2 x - 4) - 6 (x - 2)$ .

Simplify each term.

Apply the distributive property.

$3 (2 x) + 3 \cdot - 4 - 6 (x - 2) = 0$

Multiply $2$ by $3$ .

$6 x + 3 \cdot - 4 - 6 (x - 2) = 0$

Multiply $3$ by $- 4$ .

$6 x - 12 - 6 (x - 2) = 0$

Apply the distributive property.

$6 x - 12 - 6 x - 6 \cdot - 2 = 0$

Multiply $- 6$ by $- 2$ .

$6 x - 12 - 6 x + 12 = 0$

Combine the opposite terms in $6 x - 12 - 6 x + 12$ .

Subtract $6 x$ from $6 x$ .

$0 - 12 + 12 = 0$

Subtract $12$ from $0$ .

$- 12 + 12 = 0$

Add $- 12$ and $12$ .

$0 = 0$

Step 3

Since $0 = 0$ , the equation will always be true.

Always true