Solve by Factoring 3 square root of x+2=6

$3 \sqrt{x + 2} = 6$

Step 1

Subtract $6$ from both sides of the equation.

$3 \sqrt{x + 2} - 6 = 0$

Step 2

Factor $3$ out of $3 \sqrt{x + 2} - 6$ .

Factor $3$ out of $3 \sqrt{x + 2}$ .

$3 (\sqrt{x + 2}) - 6 = 0$

Factor $3$ out of $- 6$ .

$3 \sqrt{x + 2} + 3 \cdot - 2 = 0$

Factor $3$ out of $3 \sqrt{x + 2} + 3 \cdot - 2$ .

$3 (\sqrt{x + 2} - 2) = 0$

Step 3

Divide each term in $3 (\sqrt{x + 2} - 2) = 0$ by $3$ and simplify.

Divide each term in $3 (\sqrt{x + 2} - 2) = 0$ by $3$ .

$\frac{3 (\sqrt{x + 2} - 2)}{3} = \frac{0}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 (\sqrt{x + 2} - 2)}{3} = \frac{0}{3}$

Divide $\sqrt{x + 2} - 2$ by $1$ .

$\sqrt{x + 2} - 2 = \frac{0}{3}$

Simplify the right side.

Divide $0$ by $3$ .

$\sqrt{x + 2} - 2 = 0$

Step 4

Add $2$ to both sides of the equation.

$\sqrt{x + 2} = 2$

Step 5

To remove the radical on the left side of the equation, square both sides of the equation.

${\sqrt{x + 2}}^{2} = 2^{2}$

Step 6

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x + 2}$ as ${(x + 2)}^{\frac{1}{2}}$ .

${({(x + 2)}^{\frac{1}{2}})}^{2} = 2^{2}$

Simplify the left side.

Simplify ${({(x + 2)}^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${({(x + 2)}^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(x + 2)}^{\frac{1}{2} \cdot 2} = 2^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

${(x + 2)}^{\frac{1}{2} \cdot 2} = 2^{2}$

Rewrite the expression.

${(x + 2)}^{1} = 2^{2}$

Simplify.

$x + 2 = 2^{2}$

Simplify the right side.

Raise $2$ to the power of $2$ .

$x + 2 = 4$

Step 7

Move all terms not containing $x$ to the right side of the equation.

Subtract $2$ from both sides of the equation.

$x = 4 - 2$

Subtract $2$ from $4$ .

$x = 2$

Solve by Factoring 3 square root of x+2=6

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