Solve by Factoring 3x^2+14x-49=0

$3 x^{2} + 14 x - 49 = 0$

Step 1

Factor by grouping.

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 3 \cdot - 49 = - 147$ and whose sum is $b = 14$ .

Factor $14$ out of $14 x$ .

$3 x^{2} + 14 (x) - 49 = 0$

Rewrite $14$ as $- 7$ plus $21$

$3 x^{2} + (- 7 + 21) x - 49 = 0$

Apply the distributive property.

$3 x^{2} - 7 x + 21 x - 49 = 0$

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$(3 x^{2} - 7 x) + 21 x - 49 = 0$

Factor out the greatest common factor (GCF) from each group.

$x (3 x - 7) + 7 (3 x - 7) = 0$

Factor the polynomial by factoring out the greatest common factor, $3 x - 7$ .

$(3 x - 7) (x + 7) = 0$

Step 2

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$3 x - 7 = 0$

$x + 7 = 0$

Step 3

Set $3 x - 7$ equal to $0$ and solve for $x$ .

Set $3 x - 7$ equal to $0$ .

$3 x - 7 = 0$

Solve $3 x - 7 = 0$ for $x$ .

Add $7$ to both sides of the equation.

$3 x = 7$

Divide each term in $3 x = 7$ by $3$ and simplify.

Divide each term in $3 x = 7$ by $3$ .

$\frac{3 x}{3} = \frac{7}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{7}{3}$

Divide $x$ by $1$ .

$x = \frac{7}{3}$

Step 4

Set $x + 7$ equal to $0$ and solve for $x$ .

Set $x + 7$ equal to $0$ .

$x + 7 = 0$

Subtract $7$ from both sides of the equation.

$x = - 7$

Step 5

The final solution is all the values that make $(3 x - 7) (x + 7) = 0$ true.

$x = \frac{7}{3}, - 7$

Solve by Factoring 3x^2+14x-49=0

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