Solve by Factoring 3x^2+3x-36=0

$3 x^{2} + 3 x - 36 = 0$

Step 1

Factor $3$ out of $3 x^{2} + 3 x - 36$ .

Factor $3$ out of $3 x^{2}$ .

$3 (x^{2}) + 3 x - 36 = 0$

Factor $3$ out of $3 x$ .

$3 (x^{2}) + 3 (x) - 36 = 0$

Factor $3$ out of $- 36$ .

$3 (x^{2}) + 3 x + 3 \cdot - 12 = 0$

Factor $3$ out of $3 (x^{2}) + 3 x$ .

$3 (x^{2} + x) + 3 \cdot - 12 = 0$

Factor $3$ out of $3 (x^{2} + x) + 3 \cdot - 12$ .

$3 (x^{2} + x - 12) = 0$

Step 2

Factor.

Factor $x^{2} + x - 12$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 12$ and whose sum is $1$ .

$- 3, 4$

Write the factored form using these integers.

$3 ((x - 3) (x + 4)) = 0$

Remove unnecessary parentheses.

$3 (x - 3) (x + 4) = 0$

Step 3

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 3 = 0$

$x + 4 = 0$

Step 4

Set $x - 3$ equal to $0$ and solve for $x$ .

Set $x - 3$ equal to $0$ .

$x - 3 = 0$

Add $3$ to both sides of the equation.

$x = 3$

Step 5

Set $x + 4$ equal to $0$ and solve for $x$ .

Set $x + 4$ equal to $0$ .

$x + 4 = 0$

Subtract $4$ from both sides of the equation.

$x = - 4$

Step 6

The final solution is all the values that make $3 (x - 3) (x + 4) = 0$ true.

$x = 3, - 4$

Solve by Factoring 3x^2+3x-36=0

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