Solve by Factoring 3x^2+5x=6-2x

$3 x^{2} + 5 x = 6 - 2 x$

Step 1

Move all the expressions to the left side of the equation.

Subtract $6$ from both sides of the equation.

$3 x^{2} + 5 x - 6 = - 2 x$

Add $2 x$ to both sides of the equation.

$3 x^{2} + 5 x - 6 + 2 x = 0$

Step 2

Add $5 x$ and $2 x$ .

$3 x^{2} + 7 x - 6 = 0$

Step 3

Factor by grouping.

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 3 \cdot - 6 = - 18$ and whose sum is $b = 7$ .

Factor $7$ out of $7 x$ .

$3 x^{2} + 7 (x) - 6 = 0$

Rewrite $7$ as $- 2$ plus $9$

$3 x^{2} + (- 2 + 9) x - 6 = 0$

Apply the distributive property.

$3 x^{2} - 2 x + 9 x - 6 = 0$

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$(3 x^{2} - 2 x) + 9 x - 6 = 0$

Factor out the greatest common factor (GCF) from each group.

$x (3 x - 2) + 3 (3 x - 2) = 0$

Factor the polynomial by factoring out the greatest common factor, $3 x - 2$ .

$(3 x - 2) (x + 3) = 0$

Step 4

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$3 x - 2 = 0$

$x + 3 = 0$

Step 5

Set $3 x - 2$ equal to $0$ and solve for $x$ .

Set $3 x - 2$ equal to $0$ .

$3 x - 2 = 0$

Solve $3 x - 2 = 0$ for $x$ .

Add $2$ to both sides of the equation.

$3 x = 2$

Divide each term in $3 x = 2$ by $3$ and simplify.

Divide each term in $3 x = 2$ by $3$ .

$\frac{3 x}{3} = \frac{2}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{2}{3}$

Divide $x$ by $1$ .

$x = \frac{2}{3}$

Step 6

Set $x + 3$ equal to $0$ and solve for $x$ .

Set $x + 3$ equal to $0$ .

$x + 3 = 0$

Subtract $3$ from both sides of the equation.

$x = - 3$

Step 7

The final solution is all the values that make $(3 x - 2) (x + 3) = 0$ true.

$x = \frac{2}{3}, - 3$

Solve by Factoring 3x^2+5x=6-2x

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