Solve by Factoring 4(x+1)=4x+4

$4 (x + 1) = 4 x + 4$

Step 1

Move all the expressions to the left side of the equation.

Subtract $4 x$ from both sides of the equation.

$4 (x + 1) - 4 x = 4$

Subtract $4$ from both sides of the equation.

$4 (x + 1) - 4 x - 4 = 0$

Step 2

Simplify $4 (x + 1) - 4 x - 4$ .

Simplify each term.

Apply the distributive property.

$4 x + 4 \cdot 1 - 4 x - 4 = 0$

Multiply $4$ by $1$ .

$4 x + 4 - 4 x - 4 = 0$

Combine the opposite terms in $4 x + 4 - 4 x - 4$ .

Subtract $4 x$ from $4 x$ .

$0 + 4 - 4 = 0$

Add $0$ and $4$ .

$4 - 4 = 0$

Subtract $4$ from $4$ .

$0 = 0$

Step 3

Since $0 = 0$ , the equation will always be true.

Always true