Solve by Factoring -4(x+1)+6x=2(x+2)-8

$- 4 (x + 1) + 6 x = 2 (x + 2) - 8$

Step 1

Move all the expressions to the left side of the equation.

Subtract $2 (x + 2)$ from both sides of the equation.

$- 4 (x + 1) + 6 x - 2 (x + 2) = - 8$

Add $8$ to both sides of the equation.

$- 4 (x + 1) + 6 x - 2 (x + 2) + 8 = 0$

Step 2

Simplify $- 4 (x + 1) + 6 x - 2 (x + 2) + 8$ .

Simplify each term.

Apply the distributive property.

$- 4 x - 4 \cdot 1 + 6 x - 2 (x + 2) + 8 = 0$

Multiply $- 4$ by $1$ .

$- 4 x - 4 + 6 x - 2 (x + 2) + 8 = 0$

Apply the distributive property.

$- 4 x - 4 + 6 x - 2 x - 2 \cdot 2 + 8 = 0$

Multiply $- 2$ by $2$ .

$- 4 x - 4 + 6 x - 2 x - 4 + 8 = 0$

Add $- 4 x$ and $6 x$ .

$2 x - 4 - 2 x - 4 + 8 = 0$

Combine the opposite terms in $2 x - 4 - 2 x - 4 + 8$ .

Subtract $2 x$ from $2 x$ .

$0 - 4 - 4 + 8 = 0$

Subtract $4$ from $0$ .

$- 4 - 4 + 8 = 0$

Subtract $4$ from $- 4$ .

$- 8 + 8 = 0$

Add $- 8$ and $8$ .

$0 = 0$

Step 3

Since $0 = 0$ , the equation will always be true.

Always true