Solve by Factoring 4x^2+x=-7x-3

$4 x^{2} + x = - 7 x - 3$

Step 1

Move all the expressions to the left side of the equation.

Add $7 x$ to both sides of the equation.

$4 x^{2} + x + 7 x = - 3$

Add $3$ to both sides of the equation.

$4 x^{2} + x + 7 x + 3 = 0$

Step 2

Add $x$ and $7 x$ .

$4 x^{2} + 8 x + 3 = 0$

Step 3

Factor by grouping.

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 4 \cdot 3 = 12$ and whose sum is $b = 8$ .

Factor $8$ out of $8 x$ .

$4 x^{2} + 8 (x) + 3 = 0$

Rewrite $8$ as $2$ plus $6$

$4 x^{2} + (2 + 6) x + 3 = 0$

Apply the distributive property.

$4 x^{2} + 2 x + 6 x + 3 = 0$

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$(4 x^{2} + 2 x) + 6 x + 3 = 0$

Factor out the greatest common factor (GCF) from each group.

$2 x (2 x + 1) + 3 (2 x + 1) = 0$

Factor the polynomial by factoring out the greatest common factor, $2 x + 1$ .

$(2 x + 1) (2 x + 3) = 0$

Step 4

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$2 x + 1 = 0$

$2 x + 3 = 0$

Step 5

Set $2 x + 1$ equal to $0$ and solve for $x$ .

Set $2 x + 1$ equal to $0$ .

$2 x + 1 = 0$

Solve $2 x + 1 = 0$ for $x$ .

Subtract $1$ from both sides of the equation.

$2 x = - 1$

Divide each term in $2 x = - 1$ by $2$ and simplify.

Divide each term in $2 x = - 1$ by $2$ .

$\frac{2 x}{2} = \frac{- 1}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{- 1}{2}$

Divide $x$ by $1$ .

$x = \frac{- 1}{2}$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{1}{2}$

Step 6

Set $2 x + 3$ equal to $0$ and solve for $x$ .

Set $2 x + 3$ equal to $0$ .

$2 x + 3 = 0$

Solve $2 x + 3 = 0$ for $x$ .

Subtract $3$ from both sides of the equation.

$2 x = - 3$

Divide each term in $2 x = - 3$ by $2$ and simplify.

Divide each term in $2 x = - 3$ by $2$ .

$\frac{2 x}{2} = \frac{- 3}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{- 3}{2}$

Divide $x$ by $1$ .

$x = \frac{- 3}{2}$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{3}{2}$

Step 7

The final solution is all the values that make $(2 x + 1) (2 x + 3) = 0$ true.

$x = - \frac{1}{2}, - \frac{3}{2}$

Solve by Factoring 4x^2+x=-7x-3

Related Questions

Support LCMGCF.com by disabling your adblocker.