Solve by Factoring 4x^(3/2)-5=103

$4 x^{\frac{3}{2}} - 5 = 103$

Step 1

Subtract $103$ from both sides of the equation.

$4 x^{\frac{3}{2}} - 5 - 103 = 0$

Step 2

Subtract $103$ from $- 5$ .

$4 x^{\frac{3}{2}} - 108 = 0$

Step 3

Factor $4$ out of $4 x^{\frac{3}{2}} - 108$ .

Factor $4$ out of $4 x^{\frac{3}{2}}$ .

$4 (x^{\frac{3}{2}}) - 108 = 0$

Factor $4$ out of $- 108$ .

$4 x^{\frac{3}{2}} + 4 \cdot - 27 = 0$

Factor $4$ out of $4 x^{\frac{3}{2}} + 4 \cdot - 27$ .

$4 (x^{\frac{3}{2}} - 27) = 0$

Step 4

Rewrite $x^{\frac{3}{2}}$ as ${(x^{\frac{1}{2}})}^{3}$ .

$4 ({(x^{\frac{1}{2}})}^{3} - 27) = 0$

Step 5

Rewrite $27$ as $3^{3}$ .

$4 ({(x^{\frac{1}{2}})}^{3} - 3^{3}) = 0$

Step 6

Since both terms are perfect cubes, factor using the difference of cubes formula, $a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$ where $a = x^{\frac{1}{2}}$ and $b = 3$ .

$4 ((x^{\frac{1}{2}} - 3) ({(x^{\frac{1}{2}})}^{2} + x^{\frac{1}{2}} \cdot 3 + 3^{2})) = 0$

Step 7

Factor.

Simplify.

Multiply the exponents in ${(x^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$4 ((x^{\frac{1}{2}} - 3) (x^{\frac{1}{2} \cdot 2} + x^{\frac{1}{2}} \cdot 3 + 3^{2})) = 0$

Cancel the common factor of $2$ .

Cancel the common factor.

$4 ((x^{\frac{1}{2}} - 3) (x^{\frac{1}{2} \cdot 2} + x^{\frac{1}{2}} \cdot 3 + 3^{2})) = 0$

Rewrite the expression.

$4 ((x^{\frac{1}{2}} - 3) (x + x^{\frac{1}{2}} \cdot 3 + 3^{2})) = 0$

Simplify.

$4 ((x^{\frac{1}{2}} - 3) (x + x^{\frac{1}{2}} \cdot 3 + 3^{2})) = 0$

Move $3$ to the left of $x^{\frac{1}{2}}$ .

$4 ((x^{\frac{1}{2}} - 3) (x + 3 x^{\frac{1}{2}} + 3^{2})) = 0$

Raise $3$ to the power of $2$ .

$4 ((x^{\frac{1}{2}} - 3) (x + 3 x^{\frac{1}{2}} + 9)) = 0$

Remove unnecessary parentheses.

$4 (x^{\frac{1}{2}} - 3) (x + 3 x^{\frac{1}{2}} + 9) = 0$

Step 8

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x^{\frac{1}{2}} - 3 = 0$

$x + 3 x^{\frac{1}{2}} + 9 = 0$

Step 9

Set $x^{\frac{1}{2}} - 3$ equal to $0$ and solve for $x$ .

Set $x^{\frac{1}{2}} - 3$ equal to $0$ .

$x^{\frac{1}{2}} - 3 = 0$

Solve $x^{\frac{1}{2}} - 3 = 0$ for $x$ .

Add $3$ to both sides of the equation.

$x^{\frac{1}{2}} = 3$

Raise each side of the equation to the power of $2$ to eliminate the fractional exponent on the left side.

${(x^{\frac{1}{2}})}^{2} = 3^{2}$

Simplify the exponent.

Simplify the left side.

Simplify ${(x^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${(x^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x^{\frac{1}{2} \cdot 2} = 3^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

$x^{\frac{1}{2} \cdot 2} = 3^{2}$

Rewrite the expression.

$x^{1} = 3^{2}$

Simplify.

$x = 3^{2}$

Simplify the right side.

Raise $3$ to the power of $2$ .

$x = 9$

Step 10

Set $x + 3 x^{\frac{1}{2}} + 9$ equal to $0$ and solve for $x$ .

Set $x + 3 x^{\frac{1}{2}} + 9$ equal to $0$ .

$x + 3 x^{\frac{1}{2}} + 9 = 0$

Solve $x + 3 x^{\frac{1}{2}} + 9 = 0$ for $x$ .

Find a common factor $x^{\frac{1}{2}}$ that is present in each term.

${(x^{\frac{1}{2}})}^{2} + 3 x^{\frac{1}{2}} + 9$

Substitute $u$ for $x^{\frac{1}{2}}$ .

${(u)}^{2} + 3 (u) + 9 = 0$

Solve for $u$ .

Multiply $3$ by $u$ .

$u^{2} + 3 u + 9 = 0$

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Substitute the values $a = 1$ , $b = 3$ , and $c = 9$ into the quadratic formula and solve for $u$ .

$\frac{- 3 \pm \sqrt{3^{2} - 4 \cdot (1 \cdot 9)}}{2 \cdot 1}$

Simplify.

Simplify the numerator.

Raise $3$ to the power of $2$ .

$u = \frac{- 3 \pm \sqrt{9 - 4 \cdot 1 \cdot 9}}{2 \cdot 1}$

Multiply $- 4 \cdot 1 \cdot 9$ .

Multiply $- 4$ by $1$ .

$u = \frac{- 3 \pm \sqrt{9 - 4 \cdot 9}}{2 \cdot 1}$

Multiply $- 4$ by $9$ .

$u = \frac{- 3 \pm \sqrt{9 - 36}}{2 \cdot 1}$

Subtract $36$ from $9$ .

$u = \frac{- 3 \pm \sqrt{- 27}}{2 \cdot 1}$

Rewrite $- 27$ as $- 1 (27)$ .

$u = \frac{- 3 \pm \sqrt{- 1 \cdot 27}}{2 \cdot 1}$

Rewrite $\sqrt{- 1 (27)}$ as $\sqrt{- 1} \cdot \sqrt{27}$ .

$u = \frac{- 3 \pm \sqrt{- 1} \cdot \sqrt{27}}{2 \cdot 1}$

Rewrite $\sqrt{- 1}$ as $i$ .

$u = \frac{- 3 \pm i \cdot \sqrt{27}}{2 \cdot 1}$

Rewrite $27$ as $3^{2} \cdot 3$ .

Factor $9$ out of $27$ .

$u = \frac{- 3 \pm i \cdot \sqrt{9 (3)}}{2 \cdot 1}$

Rewrite $9$ as $3^{2}$ .

$u = \frac{- 3 \pm i \cdot \sqrt{3^{2} \cdot 3}}{2 \cdot 1}$

Pull terms out from under the radical.

$u = \frac{- 3 \pm i \cdot (3 \sqrt{3})}{2 \cdot 1}$

Move $3$ to the left of $i$ .

$u = \frac{- 3 \pm 3 i \sqrt{3}}{2 \cdot 1}$

Multiply $2$ by $1$ .

$u = \frac{- 3 \pm 3 i \sqrt{3}}{2}$

Simplify the expression to solve for the $+$ portion of the $\pm$ .

Simplify the numerator.

Raise $3$ to the power of $2$ .

$u = \frac{- 3 \pm \sqrt{9 - 4 \cdot 1 \cdot 9}}{2 \cdot 1}$

Multiply $- 4 \cdot 1 \cdot 9$ .

Multiply $- 4$ by $1$ .

$u = \frac{- 3 \pm \sqrt{9 - 4 \cdot 9}}{2 \cdot 1}$

Multiply $- 4$ by $9$ .

$u = \frac{- 3 \pm \sqrt{9 - 36}}{2 \cdot 1}$

Subtract $36$ from $9$ .

$u = \frac{- 3 \pm \sqrt{- 27}}{2 \cdot 1}$

Rewrite $- 27$ as $- 1 (27)$ .

$u = \frac{- 3 \pm \sqrt{- 1 \cdot 27}}{2 \cdot 1}$

Rewrite $\sqrt{- 1 (27)}$ as $\sqrt{- 1} \cdot \sqrt{27}$ .

$u = \frac{- 3 \pm \sqrt{- 1} \cdot \sqrt{27}}{2 \cdot 1}$

Rewrite $\sqrt{- 1}$ as $i$ .

$u = \frac{- 3 \pm i \cdot \sqrt{27}}{2 \cdot 1}$

Rewrite $27$ as $3^{2} \cdot 3$ .

Factor $9$ out of $27$ .

$u = \frac{- 3 \pm i \cdot \sqrt{9 (3)}}{2 \cdot 1}$

Rewrite $9$ as $3^{2}$ .

$u = \frac{- 3 \pm i \cdot \sqrt{3^{2} \cdot 3}}{2 \cdot 1}$

Pull terms out from under the radical.

$u = \frac{- 3 \pm i \cdot (3 \sqrt{3})}{2 \cdot 1}$

Move $3$ to the left of $i$ .

$u = \frac{- 3 \pm 3 i \sqrt{3}}{2 \cdot 1}$

Multiply $2$ by $1$ .

$u = \frac{- 3 \pm 3 i \sqrt{3}}{2}$

Change the $\pm$ to $+$ .

$u = \frac{- 3 + 3 i \sqrt{3}}{2}$

Rewrite $- 3$ as $- 1 (3)$ .

$u = \frac{- 1 \cdot 3 + 3 i \sqrt{3}}{2}$

Factor $- 1$ out of $3 i \sqrt{3}$ .

$u = \frac{- 1 \cdot 3 - (- 3 i \sqrt{3})}{2}$

Factor $- 1$ out of $- 1 (3) - (- 3 i \sqrt{3})$ .

$u = \frac{- 1 (3 - 3 i \sqrt{3})}{2}$

Move the negative in front of the fraction.

$u = - \frac{3 - 3 i \sqrt{3}}{2}$

Simplify the expression to solve for the $-$ portion of the $\pm$ .

Simplify the numerator.

Raise $3$ to the power of $2$ .

$u = \frac{- 3 \pm \sqrt{9 - 4 \cdot 1 \cdot 9}}{2 \cdot 1}$

Multiply $- 4 \cdot 1 \cdot 9$ .

Multiply $- 4$ by $1$ .

$u = \frac{- 3 \pm \sqrt{9 - 4 \cdot 9}}{2 \cdot 1}$

Multiply $- 4$ by $9$ .

$u = \frac{- 3 \pm \sqrt{9 - 36}}{2 \cdot 1}$

Subtract $36$ from $9$ .

$u = \frac{- 3 \pm \sqrt{- 27}}{2 \cdot 1}$

Rewrite $- 27$ as $- 1 (27)$ .

$u = \frac{- 3 \pm \sqrt{- 1 \cdot 27}}{2 \cdot 1}$

Rewrite $\sqrt{- 1 (27)}$ as $\sqrt{- 1} \cdot \sqrt{27}$ .

$u = \frac{- 3 \pm \sqrt{- 1} \cdot \sqrt{27}}{2 \cdot 1}$

Rewrite $\sqrt{- 1}$ as $i$ .

$u = \frac{- 3 \pm i \cdot \sqrt{27}}{2 \cdot 1}$

Rewrite $27$ as $3^{2} \cdot 3$ .

Factor $9$ out of $27$ .

$u = \frac{- 3 \pm i \cdot \sqrt{9 (3)}}{2 \cdot 1}$

Rewrite $9$ as $3^{2}$ .

$u = \frac{- 3 \pm i \cdot \sqrt{3^{2} \cdot 3}}{2 \cdot 1}$

Pull terms out from under the radical.

$u = \frac{- 3 \pm i \cdot (3 \sqrt{3})}{2 \cdot 1}$

Move $3$ to the left of $i$ .

$u = \frac{- 3 \pm 3 i \sqrt{3}}{2 \cdot 1}$

Multiply $2$ by $1$ .

$u = \frac{- 3 \pm 3 i \sqrt{3}}{2}$

Change the $\pm$ to $-$ .

$u = \frac{- 3 - 3 i \sqrt{3}}{2}$

Rewrite $- 3$ as $- 1 (3)$ .

$u = \frac{- 1 \cdot 3 - 3 i \sqrt{3}}{2}$

Factor $- 1$ out of $- 3 i \sqrt{3}$ .

$u = \frac{- 1 \cdot 3 - (3 i \sqrt{3})}{2}$

Factor $- 1$ out of $- 1 (3) - (3 i \sqrt{3})$ .

$u = \frac{- 1 (3 + 3 i \sqrt{3})}{2}$

Move the negative in front of the fraction.

$u = - \frac{3 + 3 i \sqrt{3}}{2}$

The final answer is the combination of both solutions.

$u = - \frac{3 - 3 i \sqrt{3}}{2}, - \frac{3 + 3 i \sqrt{3}}{2}$

Substitute $x$ for $u$ .

$x^{\frac{1}{2}} = - \frac{3 - 3 i \sqrt{3}}{2}, - \frac{3 + 3 i \sqrt{3}}{2}$

Solve for $x^{\frac{1}{2}} = - \frac{3 - 3 i \sqrt{3}}{2}$ for $x$ .

Raise each side of the equation to the power of $2$ to eliminate the fractional exponent on the left side.

${(x^{\frac{1}{2}})}^{2} = {(- \frac{3 - 3 i \sqrt{3}}{2})}^{2}$

Simplify the exponent.

Simplify the left side.

Simplify ${(x^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${(x^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x^{\frac{1}{2} \cdot 2} = {(- \frac{3 - 3 i \sqrt{3}}{2})}^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

$x^{\frac{1}{2} \cdot 2} = {(- \frac{3 - 3 i \sqrt{3}}{2})}^{2}$

Rewrite the expression.

$x^{1} = {(- \frac{3 - 3 i \sqrt{3}}{2})}^{2}$

Simplify.

$x = {(- \frac{3 - 3 i \sqrt{3}}{2})}^{2}$

Simplify the right side.

Simplify ${(- \frac{3 - 3 i \sqrt{3}}{2})}^{2}$ .

Use the power rule ${(a b)}^{n} = a^{n} b^{n}$ to distribute the exponent.

Apply the product rule to $- \frac{3 - 3 i \sqrt{3}}{2}$ .

$x = {(- 1)}^{2} {(\frac{3 - 3 i \sqrt{3}}{2})}^{2}$

Apply the product rule to $\frac{3 - 3 i \sqrt{3}}{2}$ .

$x = {(- 1)}^{2} \frac{{(3 - 3 i \sqrt{3})}^{2}}{2^{2}}$

Simplify the expression.

Raise $- 1$ to the power of $2$ .

$x = 1 \frac{{(3 - 3 i \sqrt{3})}^{2}}{2^{2}}$

Multiply $\frac{{(3 - 3 i \sqrt{3})}^{2}}{2^{2}}$ by $1$ .

$x = \frac{{(3 - 3 i \sqrt{3})}^{2}}{2^{2}}$

Raise $2$ to the power of $2$ .

$x = \frac{{(3 - 3 i \sqrt{3})}^{2}}{4}$

Rewrite ${(3 - 3 i \sqrt{3})}^{2}$ as $(3 - 3 i \sqrt{3}) (3 - 3 i \sqrt{3})$ .

$x = \frac{(3 - 3 i \sqrt{3}) (3 - 3 i \sqrt{3})}{4}$

Expand $(3 - 3 i \sqrt{3}) (3 - 3 i \sqrt{3})$ using the FOIL Method.

Apply the distributive property.

$x = \frac{3 (3 - 3 i \sqrt{3}) - 3 i \sqrt{3} (3 - 3 i \sqrt{3})}{4}$

Apply the distributive property.

$x = \frac{3 \cdot 3 + 3 (- 3 i \sqrt{3}) - 3 i \sqrt{3} (3 - 3 i \sqrt{3})}{4}$

Apply the distributive property.

$x = \frac{3 \cdot 3 + 3 (- 3 i \sqrt{3}) - 3 i \sqrt{3} \cdot 3 - 3 i \sqrt{3} (- 3 i \sqrt{3})}{4}$

Simplify and combine like terms.

Simplify each term.

Multiply $3$ by $3$ .

$x = \frac{9 + 3 (- 3 i \sqrt{3}) - 3 i \sqrt{3} \cdot 3 - 3 i \sqrt{3} (- 3 i \sqrt{3})}{4}$

Multiply $- 3$ by $3$ .

$x = \frac{9 - 9 (i \sqrt{3}) - 3 i \sqrt{3} \cdot 3 - 3 i \sqrt{3} (- 3 i \sqrt{3})}{4}$

Multiply $3$ by $- 3$ .

$x = \frac{9 - 9 i \sqrt{3} - 9 i \sqrt{3} - 3 i \sqrt{3} (- 3 i \sqrt{3})}{4}$

Multiply $- 3 i \sqrt{3} (- 3 i \sqrt{3})$ .

Multiply $- 3$ by $- 3$ .

$x = \frac{9 - 9 i \sqrt{3} - 9 i \sqrt{3} + 9 i \sqrt{3} (i \sqrt{3})}{4}$

Raise $i$ to the power of $1$ .

$x = \frac{9 - 9 i \sqrt{3} - 9 i \sqrt{3} + 9 (i^{1} i) \sqrt{3} \sqrt{3}}{4}$

Raise $i$ to the power of $1$ .

$x = \frac{9 - 9 i \sqrt{3} - 9 i \sqrt{3} + 9 (i^{1} i^{1}) \sqrt{3} \sqrt{3}}{4}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x = \frac{9 - 9 i \sqrt{3} - 9 i \sqrt{3} + 9 i^{1 + 1} \sqrt{3} \sqrt{3}}{4}$

Add $1$ and $1$ .

$x = \frac{9 - 9 i \sqrt{3} - 9 i \sqrt{3} + 9 i^{2} \sqrt{3} \sqrt{3}}{4}$

Raise $\sqrt{3}$ to the power of $1$ .

$x = \frac{9 - 9 i \sqrt{3} - 9 i \sqrt{3} + 9 i^{2} ({\sqrt{3}}^{1} \sqrt{3})}{4}$

Raise $\sqrt{3}$ to the power of $1$ .

$x = \frac{9 - 9 i \sqrt{3} - 9 i \sqrt{3} + 9 i^{2} ({\sqrt{3}}^{1} {\sqrt{3}}^{1})}{4}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x = \frac{9 - 9 i \sqrt{3} - 9 i \sqrt{3} + 9 i^{2} {\sqrt{3}}^{1 + 1}}{4}$

Add $1$ and $1$ .

$x = \frac{9 - 9 i \sqrt{3} - 9 i \sqrt{3} + 9 i^{2} {\sqrt{3}}^{2}}{4}$

Rewrite $i^{2}$ as $- 1$ .

$x = \frac{9 - 9 i \sqrt{3} - 9 i \sqrt{3} + 9 \cdot - 1 {\sqrt{3}}^{2}}{4}$

Multiply $9$ by $- 1$ .

$x = \frac{9 - 9 i \sqrt{3} - 9 i \sqrt{3} - 9 {\sqrt{3}}^{2}}{4}$

Rewrite ${\sqrt{3}}^{2}$ as $3$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{3}$ as $3^{\frac{1}{2}}$ .

$x = \frac{9 - 9 i \sqrt{3} - 9 i \sqrt{3} - 9 {(3^{\frac{1}{2}})}^{2}}{4}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x = \frac{9 - 9 i \sqrt{3} - 9 i \sqrt{3} - 9 \cdot 3^{\frac{1}{2} \cdot 2}}{4}$

Combine $\frac{1}{2}$ and $2$ .

$x = \frac{9 - 9 i \sqrt{3} - 9 i \sqrt{3} - 9 \cdot 3^{\frac{2}{2}}}{4}$

Cancel the common factor of $2$ .

Cancel the common factor.

$x = \frac{9 - 9 i \sqrt{3} - 9 i \sqrt{3} - 9 \cdot 3^{\frac{2}{2}}}{4}$

Rewrite the expression.

$x = \frac{9 - 9 i \sqrt{3} - 9 i \sqrt{3} - 9 \cdot 3^{1}}{4}$

Evaluate the exponent.

$x = \frac{9 - 9 i \sqrt{3} - 9 i \sqrt{3} - 9 \cdot 3}{4}$

Multiply $- 9$ by $3$ .

$x = \frac{9 - 9 i \sqrt{3} - 9 i \sqrt{3} - 27}{4}$

Subtract $27$ from $9$ .

$x = \frac{- 9 i \sqrt{3} - 9 i \sqrt{3} - 18}{4}$

Subtract $9 i \sqrt{3}$ from $- 9 i \sqrt{3}$ .

$x = \frac{- 18 i \sqrt{3} - 18}{4}$

Reorder $- 18 i \sqrt{3}$ and $- 18$ .

$x = \frac{- 18 - 18 i \sqrt{3}}{4}$

Cancel the common factor of $- 18 - 18 i \sqrt{3}$ and $4$ .

Factor $2$ out of $- 18$ .

$x = \frac{2 (- 9) - 18 i \sqrt{3}}{4}$

Factor $2$ out of $- 18 i \sqrt{3}$ .

$x = \frac{2 (- 9) + 2 (- 9 i \sqrt{3})}{4}$

Factor $2$ out of $2 (- 9) + 2 (- 9 i \sqrt{3})$ .

$x = \frac{2 (- 9 - 9 i \sqrt{3})}{4}$

Cancel the common factors.

Factor $2$ out of $4$ .

$x = \frac{2 (- 9 - 9 i \sqrt{3})}{2 \cdot 2}$

Cancel the common factor.

$x = \frac{2 (- 9 - 9 i \sqrt{3})}{2 \cdot 2}$

Rewrite the expression.

$x = \frac{- 9 - 9 i \sqrt{3}}{2}$

Rewrite $- 9$ as $- 1 (9)$ .

$x = \frac{- 1 (9) - 9 i \sqrt{3}}{2}$

Factor $- 1$ out of $- 9 i \sqrt{3}$ .

$x = \frac{- 1 (9) - (9 i \sqrt{3})}{2}$

Factor $- 1$ out of $- 1 (9) - (9 i \sqrt{3})$ .

$x = \frac{- 1 (9 + 9 i \sqrt{3})}{2}$

Move the negative in front of the fraction.

$x = - \frac{9 + 9 i \sqrt{3}}{2}$

Solve for $x^{\frac{1}{2}} = - \frac{3 + 3 i \sqrt{3}}{2}$ for $x$ .

Raise each side of the equation to the power of $2$ to eliminate the fractional exponent on the left side.

${(x^{\frac{1}{2}})}^{2} = {(- \frac{3 + 3 i \sqrt{3}}{2})}^{2}$

Simplify the exponent.

Simplify the left side.

Simplify ${(x^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${(x^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x^{\frac{1}{2} \cdot 2} = {(- \frac{3 + 3 i \sqrt{3}}{2})}^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

$x^{\frac{1}{2} \cdot 2} = {(- \frac{3 + 3 i \sqrt{3}}{2})}^{2}$

Rewrite the expression.

$x^{1} = {(- \frac{3 + 3 i \sqrt{3}}{2})}^{2}$

Simplify.

$x = {(- \frac{3 + 3 i \sqrt{3}}{2})}^{2}$

Simplify the right side.

Simplify ${(- \frac{3 + 3 i \sqrt{3}}{2})}^{2}$ .

Use the power rule ${(a b)}^{n} = a^{n} b^{n}$ to distribute the exponent.

Apply the product rule to $- \frac{3 + 3 i \sqrt{3}}{2}$ .

$x = {(- 1)}^{2} {(\frac{3 + 3 i \sqrt{3}}{2})}^{2}$

Apply the product rule to $\frac{3 + 3 i \sqrt{3}}{2}$ .

$x = {(- 1)}^{2} \frac{{(3 + 3 i \sqrt{3})}^{2}}{2^{2}}$

Simplify the expression.

Raise $- 1$ to the power of $2$ .

$x = 1 \frac{{(3 + 3 i \sqrt{3})}^{2}}{2^{2}}$

Multiply $\frac{{(3 + 3 i \sqrt{3})}^{2}}{2^{2}}$ by $1$ .

$x = \frac{{(3 + 3 i \sqrt{3})}^{2}}{2^{2}}$

Raise $2$ to the power of $2$ .

$x = \frac{{(3 + 3 i \sqrt{3})}^{2}}{4}$

Rewrite ${(3 + 3 i \sqrt{3})}^{2}$ as $(3 + 3 i \sqrt{3}) (3 + 3 i \sqrt{3})$ .

$x = \frac{(3 + 3 i \sqrt{3}) (3 + 3 i \sqrt{3})}{4}$

Expand $(3 + 3 i \sqrt{3}) (3 + 3 i \sqrt{3})$ using the FOIL Method.

Apply the distributive property.

$x = \frac{3 (3 + 3 i \sqrt{3}) + 3 i \sqrt{3} (3 + 3 i \sqrt{3})}{4}$

Apply the distributive property.

$x = \frac{3 \cdot 3 + 3 (3 i \sqrt{3}) + 3 i \sqrt{3} (3 + 3 i \sqrt{3})}{4}$

Apply the distributive property.

$x = \frac{3 \cdot 3 + 3 (3 i \sqrt{3}) + 3 i \sqrt{3} \cdot 3 + 3 i \sqrt{3} (3 i \sqrt{3})}{4}$

Simplify and combine like terms.

Simplify each term.

Multiply $3$ by $3$ .

$x = \frac{9 + 3 (3 i \sqrt{3}) + 3 i \sqrt{3} \cdot 3 + 3 i \sqrt{3} (3 i \sqrt{3})}{4}$

Multiply $3$ by $3$ .

$x = \frac{9 + 9 (i \sqrt{3}) + 3 i \sqrt{3} \cdot 3 + 3 i \sqrt{3} (3 i \sqrt{3})}{4}$

Multiply $3$ by $3$ .

$x = \frac{9 + 9 i \sqrt{3} + 9 i \sqrt{3} + 3 i \sqrt{3} (3 i \sqrt{3})}{4}$

Multiply $3 i \sqrt{3} (3 i \sqrt{3})$ .

Multiply $3$ by $3$ .

$x = \frac{9 + 9 i \sqrt{3} + 9 i \sqrt{3} + 9 i \sqrt{3} (i \sqrt{3})}{4}$

Raise $i$ to the power of $1$ .

$x = \frac{9 + 9 i \sqrt{3} + 9 i \sqrt{3} + 9 (i^{1} i) \sqrt{3} \sqrt{3}}{4}$

Raise $i$ to the power of $1$ .

$x = \frac{9 + 9 i \sqrt{3} + 9 i \sqrt{3} + 9 (i^{1} i^{1}) \sqrt{3} \sqrt{3}}{4}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x = \frac{9 + 9 i \sqrt{3} + 9 i \sqrt{3} + 9 i^{1 + 1} \sqrt{3} \sqrt{3}}{4}$

Add $1$ and $1$ .

$x = \frac{9 + 9 i \sqrt{3} + 9 i \sqrt{3} + 9 i^{2} \sqrt{3} \sqrt{3}}{4}$

Raise $\sqrt{3}$ to the power of $1$ .

$x = \frac{9 + 9 i \sqrt{3} + 9 i \sqrt{3} + 9 i^{2} ({\sqrt{3}}^{1} \sqrt{3})}{4}$

Raise $\sqrt{3}$ to the power of $1$ .

$x = \frac{9 + 9 i \sqrt{3} + 9 i \sqrt{3} + 9 i^{2} ({\sqrt{3}}^{1} {\sqrt{3}}^{1})}{4}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x = \frac{9 + 9 i \sqrt{3} + 9 i \sqrt{3} + 9 i^{2} {\sqrt{3}}^{1 + 1}}{4}$

Add $1$ and $1$ .

$x = \frac{9 + 9 i \sqrt{3} + 9 i \sqrt{3} + 9 i^{2} {\sqrt{3}}^{2}}{4}$

Rewrite $i^{2}$ as $- 1$ .

$x = \frac{9 + 9 i \sqrt{3} + 9 i \sqrt{3} + 9 \cdot - 1 {\sqrt{3}}^{2}}{4}$

Multiply $9$ by $- 1$ .

$x = \frac{9 + 9 i \sqrt{3} + 9 i \sqrt{3} - 9 {\sqrt{3}}^{2}}{4}$

Rewrite ${\sqrt{3}}^{2}$ as $3$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{3}$ as $3^{\frac{1}{2}}$ .

$x = \frac{9 + 9 i \sqrt{3} + 9 i \sqrt{3} - 9 {(3^{\frac{1}{2}})}^{2}}{4}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x = \frac{9 + 9 i \sqrt{3} + 9 i \sqrt{3} - 9 \cdot 3^{\frac{1}{2} \cdot 2}}{4}$

Combine $\frac{1}{2}$ and $2$ .

$x = \frac{9 + 9 i \sqrt{3} + 9 i \sqrt{3} - 9 \cdot 3^{\frac{2}{2}}}{4}$

Cancel the common factor of $2$ .

Cancel the common factor.

$x = \frac{9 + 9 i \sqrt{3} + 9 i \sqrt{3} - 9 \cdot 3^{\frac{2}{2}}}{4}$

Rewrite the expression.

$x = \frac{9 + 9 i \sqrt{3} + 9 i \sqrt{3} - 9 \cdot 3^{1}}{4}$

Evaluate the exponent.

$x = \frac{9 + 9 i \sqrt{3} + 9 i \sqrt{3} - 9 \cdot 3}{4}$

Multiply $- 9$ by $3$ .

$x = \frac{9 + 9 i \sqrt{3} + 9 i \sqrt{3} - 27}{4}$

Subtract $27$ from $9$ .

$x = \frac{9 i \sqrt{3} + 9 i \sqrt{3} - 18}{4}$

Add $9 i \sqrt{3}$ and $9 i \sqrt{3}$ .

$x = \frac{18 i \sqrt{3} - 18}{4}$

Reorder $18 i \sqrt{3}$ and $- 18$ .

$x = \frac{- 18 + 18 i \sqrt{3}}{4}$

Cancel the common factor of $- 18 + 18 i \sqrt{3}$ and $4$ .

Factor $2$ out of $- 18$ .

$x = \frac{2 (- 9) + 18 i \sqrt{3}}{4}$

Factor $2$ out of $18 i \sqrt{3}$ .

$x = \frac{2 (- 9) + 2 (9 i \sqrt{3})}{4}$

Factor $2$ out of $2 (- 9) + 2 (9 i \sqrt{3})$ .

$x = \frac{2 (- 9 + 9 i \sqrt{3})}{4}$

Cancel the common factors.

Factor $2$ out of $4$ .

$x = \frac{2 (- 9 + 9 i \sqrt{3})}{2 \cdot 2}$

Cancel the common factor.

$x = \frac{2 (- 9 + 9 i \sqrt{3})}{2 \cdot 2}$

Rewrite the expression.

$x = \frac{- 9 + 9 i \sqrt{3}}{2}$

Rewrite $- 9$ as $- 1 (9)$ .

$x = \frac{- 1 (9) + 9 i \sqrt{3}}{2}$

Factor $- 1$ out of $9 i \sqrt{3}$ .

$x = \frac{- 1 (9) - (- 9 i \sqrt{3})}{2}$

Factor $- 1$ out of $- 1 (9) - (- 9 i \sqrt{3})$ .

$x = \frac{- 1 (9 - 9 i \sqrt{3})}{2}$

Move the negative in front of the fraction.

$x = - \frac{9 - 9 i \sqrt{3}}{2}$

List all of the solutions.

$x = - \frac{9 + 9 i \sqrt{3}}{2}, - \frac{9 - 9 i \sqrt{3}}{2}$

Step 11

The final solution is all the values that make $4 (x^{\frac{1}{2}} - 3) (x + 3 x^{\frac{1}{2}} + 9) = 0$ true.

$x = 9, - \frac{9 + 9 i \sqrt{3}}{2}, - \frac{9 - 9 i \sqrt{3}}{2}$

Solve by Factoring 4x^(3/2)-5=103

Related Questions

Support LCMGCF.com by disabling your adblocker.