Solve by Factoring 4x^4-14x^2+12=0

$4 x^{4} - 14 x^{2} + 12 = 0$

Step 1

Factor $2$ out of $4 x^{4} - 14 x^{2} + 12$ .

Factor $2$ out of $4 x^{4}$ .

$2 (2 x^{4}) - 14 x^{2} + 12 = 0$

Factor $2$ out of $- 14 x^{2}$ .

$2 (2 x^{4}) + 2 (- 7 x^{2}) + 12 = 0$

Factor $2$ out of $12$ .

$2 (2 x^{4}) + 2 (- 7 x^{2}) + 2 (6) = 0$

Factor $2$ out of $2 (2 x^{4}) + 2 (- 7 x^{2})$ .

$2 (2 x^{4} - 7 x^{2}) + 2 (6) = 0$

Factor $2$ out of $2 (2 x^{4} - 7 x^{2}) + 2 (6)$ .

$2 (2 x^{4} - 7 x^{2} + 6) = 0$

Step 2

Rewrite $x^{4}$ as ${(x^{2})}^{2}$ .

$2 (2 {(x^{2})}^{2} - 7 x^{2} + 6) = 0$

Step 3

Let $u = x^{2}$ . Substitute $u$ for all occurrences of $x^{2}$ .

$2 (2 u^{2} - 7 u + 6) = 0$

Step 4

Factor by grouping.

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 2 \cdot 6 = 12$ and whose sum is $b = - 7$ .

Factor $- 7$ out of $- 7 u$ .

$2 (2 u^{2} - 7 u + 6) = 0$

Rewrite $- 7$ as $- 3$ plus $- 4$

$2 (2 u^{2} + (- 3 - 4) u + 6) = 0$

Apply the distributive property.

$2 (2 u^{2} - 3 u - 4 u + 6) = 0$

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$2 ((2 u^{2} - 3 u) - 4 u + 6) = 0$

Factor out the greatest common factor (GCF) from each group.

$2 (u (2 u - 3) - 2 (2 u - 3)) = 0$

Factor the polynomial by factoring out the greatest common factor, $2 u - 3$ .

$2 ((2 u - 3) (u - 2)) = 0$

Step 5

Factor.

Replace all occurrences of $u$ with $x^{2}$ .

$2 ((2 x^{2} - 3) (x^{2} - 2)) = 0$

Remove unnecessary parentheses.

$2 (2 x^{2} - 3) (x^{2} - 2) = 0$

Step 6

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$2 x^{2} - 3 = 0$

$x^{2} - 2 = 0$

Step 7

Set $2 x^{2} - 3$ equal to $0$ and solve for $x$ .

Set $2 x^{2} - 3$ equal to $0$ .

$2 x^{2} - 3 = 0$

Solve $2 x^{2} - 3 = 0$ for $x$ .

Add $3$ to both sides of the equation.

$2 x^{2} = 3$

Divide each term in $2 x^{2} = 3$ by $2$ and simplify.

Divide each term in $2 x^{2} = 3$ by $2$ .

$\frac{2 x^{2}}{2} = \frac{3}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x^{2}}{2} = \frac{3}{2}$

Divide $x^{2}$ by $1$ .

$x^{2} = \frac{3}{2}$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{\frac{3}{2}}$

Simplify $\pm \sqrt{\frac{3}{2}}$ .

Rewrite $\sqrt{\frac{3}{2}}$ as $\frac{\sqrt{3}}{\sqrt{2}}$ .

$x = \pm \frac{\sqrt{3}}{\sqrt{2}}$

Multiply $\frac{\sqrt{3}}{\sqrt{2}}$ by $\frac{\sqrt{2}}{\sqrt{2}}$ .

$x = \pm \frac{\sqrt{3}}{\sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}}$

Combine and simplify the denominator.

Multiply $\frac{\sqrt{3}}{\sqrt{2}}$ by $\frac{\sqrt{2}}{\sqrt{2}}$ .

$x = \pm \frac{\sqrt{3} \sqrt{2}}{\sqrt{2} \sqrt{2}}$

Raise $\sqrt{2}$ to the power of $1$ .

$x = \pm \frac{\sqrt{3} \sqrt{2}}{{\sqrt{2}}^{1} \sqrt{2}}$

Raise $\sqrt{2}$ to the power of $1$ .

$x = \pm \frac{\sqrt{3} \sqrt{2}}{{\sqrt{2}}^{1} {\sqrt{2}}^{1}}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x = \pm \frac{\sqrt{3} \sqrt{2}}{{\sqrt{2}}^{1 + 1}}$

Add $1$ and $1$ .

$x = \pm \frac{\sqrt{3} \sqrt{2}}{{\sqrt{2}}^{2}}$

Rewrite ${\sqrt{2}}^{2}$ as $2$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{2}$ as $2^{\frac{1}{2}}$ .

$x = \pm \frac{\sqrt{3} \sqrt{2}}{{(2^{\frac{1}{2}})}^{2}}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x = \pm \frac{\sqrt{3} \sqrt{2}}{2^{\frac{1}{2} \cdot 2}}$

Combine $\frac{1}{2}$ and $2$ .

$x = \pm \frac{\sqrt{3} \sqrt{2}}{2^{\frac{2}{2}}}$

Cancel the common factor of $2$ .

Cancel the common factor.

$x = \pm \frac{\sqrt{3} \sqrt{2}}{2^{\frac{2}{2}}}$

Rewrite the expression.

$x = \pm \frac{\sqrt{3} \sqrt{2}}{2^{1}}$

Evaluate the exponent.

$x = \pm \frac{\sqrt{3} \sqrt{2}}{2}$

Simplify the numerator.

Combine using the product rule for radicals.

$x = \pm \frac{\sqrt{3 \cdot 2}}{2}$

Multiply $3$ by $2$ .

$x = \pm \frac{\sqrt{6}}{2}$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x = \frac{\sqrt{6}}{2}$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - \frac{\sqrt{6}}{2}$

The complete solution is the result of both the positive and negative portions of the solution.

$x = \frac{\sqrt{6}}{2}, - \frac{\sqrt{6}}{2}$

Step 8

Set $x^{2} - 2$ equal to $0$ and solve for $x$ .

Set $x^{2} - 2$ equal to $0$ .

$x^{2} - 2 = 0$

Solve $x^{2} - 2 = 0$ for $x$ .

Add $2$ to both sides of the equation.

$x^{2} = 2$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{2}$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x = \sqrt{2}$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - \sqrt{2}$

The complete solution is the result of both the positive and negative portions of the solution.

$x = \sqrt{2}, - \sqrt{2}$

Step 9

The final solution is all the values that make $2 (2 x^{2} - 3) (x^{2} - 2) = 0$ true.

$x = \frac{\sqrt{6}}{2}, - \frac{\sqrt{6}}{2}, \sqrt{2}, - \sqrt{2}$

Step 10

The result can be shown in multiple forms.

Exact Form:

$x = \frac{\sqrt{6}}{2}, - \frac{\sqrt{6}}{2}, \sqrt{2}, - \sqrt{2}$

Decimal Form:

$x = 1.22474487 \dots, - 1.22474487 \dots, 1.41421356 \dots, - 1.41421356 \dots$

Solve by Factoring 4x^4-14x^2+12=0

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