Solve by Factoring 5(2x-31)=10x-155

$5 (2 x - 31) = 10 x - 155$

Step 1

Move all the expressions to the left side of the equation.

Subtract $10 x$ from both sides of the equation.

$5 (2 x - 31) - 10 x = - 155$

Add $155$ to both sides of the equation.

$5 (2 x - 31) - 10 x + 155 = 0$

Step 2

Simplify $5 (2 x - 31) - 10 x + 155$ .

Simplify each term.

Apply the distributive property.

$5 (2 x) + 5 \cdot - 31 - 10 x + 155 = 0$

Multiply $2$ by $5$ .

$10 x + 5 \cdot - 31 - 10 x + 155 = 0$

Multiply $5$ by $- 31$ .

$10 x - 155 - 10 x + 155 = 0$

Combine the opposite terms in $10 x - 155 - 10 x + 155$ .

Subtract $10 x$ from $10 x$ .

$0 - 155 + 155 = 0$

Subtract $155$ from $0$ .

$- 155 + 155 = 0$

Add $- 155$ and $155$ .

$0 = 0$

Step 3

Since $0 = 0$ , the equation will always be true.

Always true