Solve by Factoring 6x^2+3x=0

$6 x^{2} + 3 x = 0$

Step 1

Factor $3 x$ out of $6 x^{2} + 3 x$ .

Factor $3 x$ out of $6 x^{2}$ .

$3 x (2 x) + 3 x = 0$

Factor $3 x$ out of $3 x$ .

$3 x (2 x) + 3 x (1) = 0$

Factor $3 x$ out of $3 x (2 x) + 3 x (1)$ .

$3 x (2 x + 1) = 0$

Step 2

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x = 0$

$2 x + 1 = 0$

Step 3

Set $x$ equal to $0$ .

$x = 0$

Step 4

Set $2 x + 1$ equal to $0$ and solve for $x$ .

Set $2 x + 1$ equal to $0$ .

$2 x + 1 = 0$

Solve $2 x + 1 = 0$ for $x$ .

Subtract $1$ from both sides of the equation.

$2 x = - 1$

Divide each term in $2 x = - 1$ by $2$ and simplify.

Divide each term in $2 x = - 1$ by $2$ .

$\frac{2 x}{2} = \frac{- 1}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{- 1}{2}$

Divide $x$ by $1$ .

$x = \frac{- 1}{2}$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{1}{2}$

Step 5

The final solution is all the values that make $3 x (2 x + 1) = 0$ true.

$x = 0, - \frac{1}{2}$