Solve by Factoring 6y^2+18y=0

$6 y^{2} + 18 y = 0$

Step 1

Factor $6 y$ out of $6 y^{2} + 18 y$ .

Factor $6 y$ out of $6 y^{2}$ .

$6 y (y) + 18 y = 0$

Factor $6 y$ out of $18 y$ .

$6 y (y) + 6 y (3) = 0$

Factor $6 y$ out of $6 y (y) + 6 y (3)$ .

$6 y (y + 3) = 0$

Step 2

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$y = 0$

$y + 3 = 0$

Step 3

Set $y$ equal to $0$ .

$y = 0$

Step 4

Set $y + 3$ equal to $0$ and solve for $y$ .

Set $y + 3$ equal to $0$ .

$y + 3 = 0$

Subtract $3$ from both sides of the equation.

$y = - 3$

Step 5

The final solution is all the values that make $6 y (y + 3) = 0$ true.

$y = 0, - 3$