Solve by Factoring 6y+9=3(2y+3)

$6 y + 9 = 3 (2 y + 3)$

Step 1

Subtract $3 (2 y + 3)$ from both sides of the equation.

$6 y + 9 - 3 (2 y + 3) = 0$

Step 2

Simplify $6 y + 9 - 3 (2 y + 3)$ .

Simplify each term.

Apply the distributive property.

$6 y + 9 - 3 (2 y) - 3 \cdot 3 = 0$

Multiply $2$ by $- 3$ .

$6 y + 9 - 6 y - 3 \cdot 3 = 0$

Multiply $- 3$ by $3$ .

$6 y + 9 - 6 y - 9 = 0$

Combine the opposite terms in $6 y + 9 - 6 y - 9$ .

Subtract $6 y$ from $6 y$ .

$0 + 9 - 9 = 0$

Add $0$ and $9$ .

$9 - 9 = 0$

Subtract $9$ from $9$ .

$0 = 0$

Step 3

Since $0 = 0$ , the equation will always be true.

Always true