Solve by Factoring 9x^2+8x=0

$9 x^{2} + 8 x = 0$

Step 1

Factor $x$ out of $9 x^{2} + 8 x$ .

Factor $x$ out of $9 x^{2}$ .

$x (9 x) + 8 x = 0$

Factor $x$ out of $8 x$ .

$x (9 x) + x \cdot 8 = 0$

Factor $x$ out of $x (9 x) + x \cdot 8$ .

$x (9 x + 8) = 0$

Step 2

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x = 0$

$9 x + 8 = 0$

Step 3

Set $x$ equal to $0$ .

$x = 0$

Step 4

Set $9 x + 8$ equal to $0$ and solve for $x$ .

Set $9 x + 8$ equal to $0$ .

$9 x + 8 = 0$

Solve $9 x + 8 = 0$ for $x$ .

Subtract $8$ from both sides of the equation.

$9 x = - 8$

Divide each term in $9 x = - 8$ by $9$ and simplify.

Divide each term in $9 x = - 8$ by $9$ .

$\frac{9 x}{9} = \frac{- 8}{9}$

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{9 x}{9} = \frac{- 8}{9}$

Divide $x$ by $1$ .

$x = \frac{- 8}{9}$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{8}{9}$

Step 5

The final solution is all the values that make $x (9 x + 8) = 0$ true.

$x = 0, - \frac{8}{9}$