Solve by Factoring (k+1)(k-5)=0

$(k + 1) (k - 5) = 0$

Step 1

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$k + 1 = 0$

$k - 5 = 0$

Step 2

Set $k + 1$ equal to $0$ and solve for $k$ .

Set $k + 1$ equal to $0$ .

$k + 1 = 0$

Subtract $1$ from both sides of the equation.

$k = - 1$

Step 3

Set $k - 5$ equal to $0$ and solve for $k$ .

Set $k - 5$ equal to $0$ .

$k - 5 = 0$

Add $5$ to both sides of the equation.

$k = 5$

Step 4

The final solution is all the values that make $(k + 1) (k - 5) = 0$ true.

$k = - 1, 5$