Solve by Factoring m^2+2m-24=0

$m^{2} + 2 m - 24 = 0$

Step 1

Factor $m^{2} + 2 m - 24$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 24$ and whose sum is $2$ .

$- 4, 6$

Write the factored form using these integers.

$(m - 4) (m + 6) = 0$

Step 2

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$m - 4 = 0$

$m + 6 = 0$

Step 3

Set $m - 4$ equal to $0$ and solve for $m$ .

Set $m - 4$ equal to $0$ .

$m - 4 = 0$

Add $4$ to both sides of the equation.

$m = 4$

Step 4

Set $m + 6$ equal to $0$ and solve for $m$ .

Set $m + 6$ equal to $0$ .

$m + 6 = 0$

Subtract $6$ from both sides of the equation.

$m = - 6$

Step 5

The final solution is all the values that make $(m - 4) (m + 6) = 0$ true.

$m = 4, - 6$

Solve by Factoring m^2+2m-24=0

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