Solve by Factoring n^2+2n-15=0

$n^{2} + 2 n - 15 = 0$

Step 1

Factor $n^{2} + 2 n - 15$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 15$ and whose sum is $2$ .

$- 3, 5$

Write the factored form using these integers.

$(n - 3) (n + 5) = 0$

Step 2

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$n - 3 = 0$

$n + 5 = 0$

Step 3

Set $n - 3$ equal to $0$ and solve for $n$ .

Set $n - 3$ equal to $0$ .

$n - 3 = 0$

Add $3$ to both sides of the equation.

$n = 3$

Step 4

Set $n + 5$ equal to $0$ and solve for $n$ .

Set $n + 5$ equal to $0$ .

$n + 5 = 0$

Subtract $5$ from both sides of the equation.

$n = - 5$

Step 5

The final solution is all the values that make $(n - 3) (n + 5) = 0$ true.

$n = 3, - 5$

Solve by Factoring n^2+2n-15=0

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