Solve by Factoring square root of 2x-7-2=1

$\sqrt{2 x - 7} - 2 = 1$

Step 1

Subtract $1$ from both sides of the equation.

$\sqrt{2 x - 7} - 2 - 1 = 0$

Step 2

Subtract $1$ from $- 2$ .

$\sqrt{2 x - 7} - 3 = 0$

Step 3

Add $3$ to both sides of the equation.

$\sqrt{2 x - 7} = 3$

Step 4

To remove the radical on the left side of the equation, square both sides of the equation.

${\sqrt{2 x - 7}}^{2} = 3^{2}$

Step 5

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{2 x - 7}$ as ${(2 x - 7)}^{\frac{1}{2}}$ .

${({(2 x - 7)}^{\frac{1}{2}})}^{2} = 3^{2}$

Simplify the left side.

Simplify ${({(2 x - 7)}^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${({(2 x - 7)}^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(2 x - 7)}^{\frac{1}{2} \cdot 2} = 3^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

${(2 x - 7)}^{\frac{1}{2} \cdot 2} = 3^{2}$

Rewrite the expression.

${(2 x - 7)}^{1} = 3^{2}$

Simplify.

$2 x - 7 = 3^{2}$

Simplify the right side.

Raise $3$ to the power of $2$ .

$2 x - 7 = 9$

Step 6

Solve for $x$ .

Move all terms not containing $x$ to the right side of the equation.

Add $7$ to both sides of the equation.

$2 x = 9 + 7$

Add $9$ and $7$ .

$2 x = 16$

Divide each term in $2 x = 16$ by $2$ and simplify.

Divide each term in $2 x = 16$ by $2$ .

$\frac{2 x}{2} = \frac{16}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{16}{2}$

Divide $x$ by $1$ .

$x = \frac{16}{2}$

Simplify the right side.

Divide $16$ by $2$ .

$x = 8$

Solve by Factoring square root of 2x-7-2=1

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