Solve by Factoring square root of 48-2x=x

$\sqrt{48 - 2 x} = x$

Step 1

Subtract $x$ from both sides of the equation.

$\sqrt{48 - 2 x} - x = 0$

Step 2

Factor $2$ out of $48 - 2 x$ .

Factor $2$ out of $48$ .

$\sqrt{2 (24) - 2 x} - x = 0$

Factor $2$ out of $- 2 x$ .

$\sqrt{2 (24) + 2 (- x)} - x = 0$

Factor $2$ out of $2 (24) + 2 (- x)$ .

$\sqrt{2 (24 - x)} - x = 0$

Step 3

Add $x$ to both sides of the equation.

$\sqrt{2 (24 - x)} = x$

Step 4

To remove the radical on the left side of the equation, square both sides of the equation.

${\sqrt{2 (24 - x)}}^{2} = x^{2}$

Step 5

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{2 (24 - x)}$ as ${(2 (24 - x))}^{\frac{1}{2}}$ .

${({(2 (24 - x))}^{\frac{1}{2}})}^{2} = x^{2}$

Simplify the left side.

Simplify ${({(2 (24 - x))}^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${({(2 (24 - x))}^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(2 (24 - x))}^{\frac{1}{2} \cdot 2} = x^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

${(2 (24 - x))}^{\frac{1}{2} \cdot 2} = x^{2}$

Rewrite the expression.

${(2 (24 - x))}^{1} = x^{2}$

Apply the distributive property.

${(2 \cdot 24 + 2 (- x))}^{1} = x^{2}$

Multiply.

Multiply $2$ by $24$ .

${(48 + 2 (- x))}^{1} = x^{2}$

Multiply $- 1$ by $2$ .

${(48 - 2 x)}^{1} = x^{2}$

Simplify.

$48 - 2 x = x^{2}$

Step 6

Solve for $x$ .

Subtract $x^{2}$ from both sides of the equation.

$48 - 2 x - x^{2} = 0$

Factor the left side of the equation.

Factor $- 1$ out of $48 - 2 x - x^{2}$ .

Reorder the expression.

Move $48$ .

$- 2 x - x^{2} + 48 = 0$

Reorder $- 2 x$ and $- x^{2}$ .

$- x^{2} - 2 x + 48 = 0$

Factor $- 1$ out of $- x^{2}$ .

$- (x^{2}) - 2 x + 48 = 0$

Factor $- 1$ out of $- 2 x$ .

$- (x^{2}) - (2 x) + 48 = 0$

Rewrite $48$ as $- 1 (- 48)$ .

$- (x^{2}) - (2 x) - 1 \cdot - 48 = 0$

Factor $- 1$ out of $- (x^{2}) - (2 x)$ .

$- (x^{2} + 2 x) - 1 \cdot - 48 = 0$

Factor $- 1$ out of $- (x^{2} + 2 x) - 1 (- 48)$ .

$- (x^{2} + 2 x - 48) = 0$

Factor.

Factor $x^{2} + 2 x - 48$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 48$ and whose sum is $2$ .

$- 6, 8$

Write the factored form using these integers.

$- ((x - 6) (x + 8)) = 0$

Remove unnecessary parentheses.

$- (x - 6) (x + 8) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 6 = 0$

$x + 8 = 0$

Set $x - 6$ equal to $0$ and solve for $x$ .

Set $x - 6$ equal to $0$ .

$x - 6 = 0$

Add $6$ to both sides of the equation.

$x = 6$

Set $x + 8$ equal to $0$ and solve for $x$ .

Set $x + 8$ equal to $0$ .

$x + 8 = 0$

Subtract $8$ from both sides of the equation.

$x = - 8$

The final solution is all the values that make $- (x - 6) (x + 8) = 0$ true.

$x = 6, - 8$

Step 7

Exclude the solutions that do not make $\sqrt{2 (24 - x)} - x = 0$ true.

$x = 6$

Solve by Factoring square root of 48-2x=x

Related Questions

Support LCMGCF.com by disabling your adblocker.