Solve by Factoring square root of 4x-5=1

$\sqrt{4 x - 5} = 1$

Step 1

Subtract $1$ from both sides of the equation.

$\sqrt{4 x - 5} - 1 = 0$

Step 2

Add $1$ to both sides of the equation.

$\sqrt{4 x - 5} = 1$

Step 3

To remove the radical on the left side of the equation, square both sides of the equation.

${\sqrt{4 x - 5}}^{2} = 1^{2}$

Step 4

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{4 x - 5}$ as ${(4 x - 5)}^{\frac{1}{2}}$ .

${({(4 x - 5)}^{\frac{1}{2}})}^{2} = 1^{2}$

Simplify the left side.

Simplify ${({(4 x - 5)}^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${({(4 x - 5)}^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(4 x - 5)}^{\frac{1}{2} \cdot 2} = 1^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

${(4 x - 5)}^{\frac{1}{2} \cdot 2} = 1^{2}$

Rewrite the expression.

${(4 x - 5)}^{1} = 1^{2}$

Simplify.

$4 x - 5 = 1^{2}$

Simplify the right side.

One to any power is one.

$4 x - 5 = 1$

Step 5

Solve for $x$ .

Move all terms not containing $x$ to the right side of the equation.

Add $5$ to both sides of the equation.

$4 x = 1 + 5$

Add $1$ and $5$ .

$4 x = 6$

Divide each term in $4 x = 6$ by $4$ and simplify.

Divide each term in $4 x = 6$ by $4$ .

$\frac{4 x}{4} = \frac{6}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 x}{4} = \frac{6}{4}$

Divide $x$ by $1$ .

$x = \frac{6}{4}$

Simplify the right side.

Cancel the common factor of $6$ and $4$ .

Factor $2$ out of $6$ .

$x = \frac{2 (3)}{4}$

Cancel the common factors.

Factor $2$ out of $4$ .

$x = \frac{2 \cdot 3}{2 \cdot 2}$

Cancel the common factor.

$x = \frac{2 \cdot 3}{2 \cdot 2}$

Rewrite the expression.

$x = \frac{3}{2}$

Solve by Factoring square root of 4x-5=1

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