Solve by Factoring square root of 4y+1- square root of y-2=3

$\sqrt{4 y + 1} - \sqrt{y - 2} = 3$

Step 1

Subtract $3$ from both sides of the equation.

$\sqrt{4 y + 1} - \sqrt{y - 2} - 3 = 0$

Step 2

Move all terms not containing $\sqrt{4 y + 1}$ to the right side of the equation.

Add $\sqrt{y - 2}$ to both sides of the equation.

$\sqrt{4 y + 1} - 3 = \sqrt{y - 2}$

Add $3$ to both sides of the equation.

$\sqrt{4 y + 1} = \sqrt{y - 2} + 3$

Step 3

To remove the radical on the left side of the equation, square both sides of the equation.

${\sqrt{4 y + 1}}^{2} = {(\sqrt{y - 2} + 3)}^{2}$

Step 4

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{4 y + 1}$ as ${(4 y + 1)}^{\frac{1}{2}}$ .

${({(4 y + 1)}^{\frac{1}{2}})}^{2} = {(\sqrt{y - 2} + 3)}^{2}$

Simplify the left side.

Simplify ${({(4 y + 1)}^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${({(4 y + 1)}^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(4 y + 1)}^{\frac{1}{2} \cdot 2} = {(\sqrt{y - 2} + 3)}^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

${(4 y + 1)}^{\frac{1}{2} \cdot 2} = {(\sqrt{y - 2} + 3)}^{2}$

Rewrite the expression.

${(4 y + 1)}^{1} = {(\sqrt{y - 2} + 3)}^{2}$

Simplify.

$4 y + 1 = {(\sqrt{y - 2} + 3)}^{2}$

Simplify the right side.

Simplify ${(\sqrt{y - 2} + 3)}^{2}$ .

Rewrite ${(\sqrt{y - 2} + 3)}^{2}$ as $(\sqrt{y - 2} + 3) (\sqrt{y - 2} + 3)$ .

$4 y + 1 = (\sqrt{y - 2} + 3) (\sqrt{y - 2} + 3)$

Expand $(\sqrt{y - 2} + 3) (\sqrt{y - 2} + 3)$ using the FOIL Method.

Apply the distributive property.

$4 y + 1 = \sqrt{y - 2} (\sqrt{y - 2} + 3) + 3 (\sqrt{y - 2} + 3)$

Apply the distributive property.

$4 y + 1 = \sqrt{y - 2} \sqrt{y - 2} + \sqrt{y - 2} \cdot 3 + 3 (\sqrt{y - 2} + 3)$

Apply the distributive property.

$4 y + 1 = \sqrt{y - 2} \sqrt{y - 2} + \sqrt{y - 2} \cdot 3 + 3 \sqrt{y - 2} + 3 \cdot 3$

Simplify and combine like terms.

Simplify each term.

Multiply $\sqrt{y - 2} \sqrt{y - 2}$ .

Raise $\sqrt{y - 2}$ to the power of $1$ .

$4 y + 1 = {\sqrt{y - 2}}^{1} \sqrt{y - 2} + \sqrt{y - 2} \cdot 3 + 3 \sqrt{y - 2} + 3 \cdot 3$

Raise $\sqrt{y - 2}$ to the power of $1$ .

$4 y + 1 = {\sqrt{y - 2}}^{1} {\sqrt{y - 2}}^{1} + \sqrt{y - 2} \cdot 3 + 3 \sqrt{y - 2} + 3 \cdot 3$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$4 y + 1 = {\sqrt{y - 2}}^{1 + 1} + \sqrt{y - 2} \cdot 3 + 3 \sqrt{y - 2} + 3 \cdot 3$

Add $1$ and $1$ .

$4 y + 1 = {\sqrt{y - 2}}^{2} + \sqrt{y - 2} \cdot 3 + 3 \sqrt{y - 2} + 3 \cdot 3$

Rewrite ${\sqrt{y - 2}}^{2}$ as $y - 2$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{y - 2}$ as ${(y - 2)}^{\frac{1}{2}}$ .

$4 y + 1 = {({(y - 2)}^{\frac{1}{2}})}^{2} + \sqrt{y - 2} \cdot 3 + 3 \sqrt{y - 2} + 3 \cdot 3$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$4 y + 1 = {(y - 2)}^{\frac{1}{2} \cdot 2} + \sqrt{y - 2} \cdot 3 + 3 \sqrt{y - 2} + 3 \cdot 3$

Combine $\frac{1}{2}$ and $2$ .

$4 y + 1 = {(y - 2)}^{\frac{2}{2}} + \sqrt{y - 2} \cdot 3 + 3 \sqrt{y - 2} + 3 \cdot 3$

Cancel the common factor of $2$ .

Cancel the common factor.

$4 y + 1 = {(y - 2)}^{\frac{2}{2}} + \sqrt{y - 2} \cdot 3 + 3 \sqrt{y - 2} + 3 \cdot 3$

Rewrite the expression.

$4 y + 1 = {(y - 2)}^{1} + \sqrt{y - 2} \cdot 3 + 3 \sqrt{y - 2} + 3 \cdot 3$

Simplify.

$4 y + 1 = y - 2 + \sqrt{y - 2} \cdot 3 + 3 \sqrt{y - 2} + 3 \cdot 3$

Move $3$ to the left of $\sqrt{y - 2}$ .

$4 y + 1 = y - 2 + 3 \cdot \sqrt{y - 2} + 3 \sqrt{y - 2} + 3 \cdot 3$

Multiply $3$ by $3$ .

$4 y + 1 = y - 2 + 3 \sqrt{y - 2} + 3 \sqrt{y - 2} + 9$

Add $- 2$ and $9$ .

$4 y + 1 = y + 7 + 3 \sqrt{y - 2} + 3 \sqrt{y - 2}$

Add $3 \sqrt{y - 2}$ and $3 \sqrt{y - 2}$ .

$4 y + 1 = y + 7 + 6 \sqrt{y - 2}$

Step 5

Solve for $6 \sqrt{y - 2}$ .

Rewrite the equation as $y + 7 + 6 \sqrt{y - 2} = 4 y + 1$ .

$y + 7 + 6 \sqrt{y - 2} = 4 y + 1$

Move all terms not containing $6 \sqrt{y - 2}$ to the right side of the equation.

Subtract $y$ from both sides of the equation.

$7 + 6 \sqrt{y - 2} = 4 y + 1 - y$

Subtract $7$ from both sides of the equation.

$6 \sqrt{y - 2} = 4 y + 1 - y - 7$

Subtract $y$ from $4 y$ .

$6 \sqrt{y - 2} = 3 y + 1 - 7$

Subtract $7$ from $1$ .

$6 \sqrt{y - 2} = 3 y - 6$

Step 6

To remove the radical on the left side of the equation, square both sides of the equation.

${(6 \sqrt{y - 2})}^{2} = {(3 y - 6)}^{2}$

Step 7

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{y - 2}$ as ${(y - 2)}^{\frac{1}{2}}$ .

${(6 {(y - 2)}^{\frac{1}{2}})}^{2} = {(3 y - 6)}^{2}$

Simplify the left side.

Simplify ${(6 {(y - 2)}^{\frac{1}{2}})}^{2}$ .

Apply the product rule to $6 {(y - 2)}^{\frac{1}{2}}$ .

$6^{2} {({(y - 2)}^{\frac{1}{2}})}^{2} = {(3 y - 6)}^{2}$

Raise $6$ to the power of $2$ .

$36 {({(y - 2)}^{\frac{1}{2}})}^{2} = {(3 y - 6)}^{2}$

Multiply the exponents in ${({(y - 2)}^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$36 {(y - 2)}^{\frac{1}{2} \cdot 2} = {(3 y - 6)}^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

$36 {(y - 2)}^{\frac{1}{2} \cdot 2} = {(3 y - 6)}^{2}$

Rewrite the expression.

$36 {(y - 2)}^{1} = {(3 y - 6)}^{2}$

Simplify.

$36 (y - 2) = {(3 y - 6)}^{2}$

Apply the distributive property.

$36 y + 36 \cdot - 2 = {(3 y - 6)}^{2}$

Multiply $36$ by $- 2$ .

$36 y - 72 = {(3 y - 6)}^{2}$

Simplify the right side.

Simplify ${(3 y - 6)}^{2}$ .

Rewrite ${(3 y - 6)}^{2}$ as $(3 y - 6) (3 y - 6)$ .

$36 y - 72 = (3 y - 6) (3 y - 6)$

Expand $(3 y - 6) (3 y - 6)$ using the FOIL Method.

Apply the distributive property.

$36 y - 72 = 3 y (3 y - 6) - 6 (3 y - 6)$

Apply the distributive property.

$36 y - 72 = 3 y (3 y) + 3 y \cdot - 6 - 6 (3 y - 6)$

Apply the distributive property.

$36 y - 72 = 3 y (3 y) + 3 y \cdot - 6 - 6 (3 y) - 6 \cdot - 6$

Simplify and combine like terms.

Simplify each term.

Rewrite using the commutative property of multiplication.

$36 y - 72 = 3 \cdot 3 y \cdot y + 3 y \cdot - 6 - 6 (3 y) - 6 \cdot - 6$

Multiply $y$ by $y$ by adding the exponents.

Move $y$ .

$36 y - 72 = 3 \cdot 3 (y \cdot y) + 3 y \cdot - 6 - 6 (3 y) - 6 \cdot - 6$

Multiply $y$ by $y$ .

$36 y - 72 = 3 \cdot 3 y^{2} + 3 y \cdot - 6 - 6 (3 y) - 6 \cdot - 6$

Multiply $3$ by $3$ .

$36 y - 72 = 9 y^{2} + 3 y \cdot - 6 - 6 (3 y) - 6 \cdot - 6$

Multiply $- 6$ by $3$ .

$36 y - 72 = 9 y^{2} - 18 y - 6 (3 y) - 6 \cdot - 6$

Multiply $3$ by $- 6$ .

$36 y - 72 = 9 y^{2} - 18 y - 18 y - 6 \cdot - 6$

Multiply $- 6$ by $- 6$ .

$36 y - 72 = 9 y^{2} - 18 y - 18 y + 36$

Subtract $18 y$ from $- 18 y$ .

$36 y - 72 = 9 y^{2} - 36 y + 36$

Step 8

Solve for $y$ .

Since $y$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$9 y^{2} - 36 y + 36 = 36 y - 72$

Move all terms containing $y$ to the left side of the equation.

Subtract $36 y$ from both sides of the equation.

$9 y^{2} - 36 y + 36 - 36 y = - 72$

Subtract $36 y$ from $- 36 y$ .

$9 y^{2} - 72 y + 36 = - 72$

Add $72$ to both sides of the equation.

$9 y^{2} - 72 y + 36 + 72 = 0$

Add $36$ and $72$ .

$9 y^{2} - 72 y + 108 = 0$

Factor the left side of the equation.

Factor $9$ out of $9 y^{2} - 72 y + 108$ .

Factor $9$ out of $9 y^{2}$ .

$9 (y^{2}) - 72 y + 108 = 0$

Factor $9$ out of $- 72 y$ .

$9 (y^{2}) + 9 (- 8 y) + 108 = 0$

Factor $9$ out of $108$ .

$9 y^{2} + 9 (- 8 y) + 9 \cdot 12 = 0$

Factor $9$ out of $9 y^{2} + 9 (- 8 y)$ .

$9 (y^{2} - 8 y) + 9 \cdot 12 = 0$

Factor $9$ out of $9 (y^{2} - 8 y) + 9 \cdot 12$ .

$9 (y^{2} - 8 y + 12) = 0$

Factor.

Factor $y^{2} - 8 y + 12$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $12$ and whose sum is $- 8$ .

$- 6, - 2$

Write the factored form using these integers.

$9 ((y - 6) (y - 2)) = 0$

Remove unnecessary parentheses.

$9 (y - 6) (y - 2) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$y - 6 = 0$

$y - 2 = 0$

Set $y - 6$ equal to $0$ and solve for $y$ .

Set $y - 6$ equal to $0$ .

$y - 6 = 0$

Add $6$ to both sides of the equation.

$y = 6$

Set $y - 2$ equal to $0$ and solve for $y$ .

Set $y - 2$ equal to $0$ .

$y - 2 = 0$

Add $2$ to both sides of the equation.

$y = 2$

The final solution is all the values that make $9 (y - 6) (y - 2) = 0$ true.

$y = 6, 2$

Solve by Factoring square root of 4y+1- square root of y-2=3

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