Solve by Factoring square root of x+5-1=4

$\sqrt{x + 5} - 1 = 4$

Step 1

Subtract $4$ from both sides of the equation.

$\sqrt{x + 5} - 1 - 4 = 0$

Step 2

Subtract $4$ from $- 1$ .

$\sqrt{x + 5} - 5 = 0$

Step 3

Add $5$ to both sides of the equation.

$\sqrt{x + 5} = 5$

Step 4

To remove the radical on the left side of the equation, square both sides of the equation.

${\sqrt{x + 5}}^{2} = 5^{2}$

Step 5

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x + 5}$ as ${(x + 5)}^{\frac{1}{2}}$ .

${({(x + 5)}^{\frac{1}{2}})}^{2} = 5^{2}$

Simplify the left side.

Simplify ${({(x + 5)}^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${({(x + 5)}^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(x + 5)}^{\frac{1}{2} \cdot 2} = 5^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

${(x + 5)}^{\frac{1}{2} \cdot 2} = 5^{2}$

Rewrite the expression.

${(x + 5)}^{1} = 5^{2}$

Simplify.

$x + 5 = 5^{2}$

Simplify the right side.

Raise $5$ to the power of $2$ .

$x + 5 = 25$

Step 6

Move all terms not containing $x$ to the right side of the equation.

Subtract $5$ from both sides of the equation.

$x = 25 - 5$

Subtract $5$ from $25$ .

$x = 20$