Solve by Factoring square root of x-6=5

$\sqrt{x - 6} = 5$

Step 1

Subtract $5$ from both sides of the equation.

$\sqrt{x - 6} - 5 = 0$

Step 2

Add $5$ to both sides of the equation.

$\sqrt{x - 6} = 5$

Step 3

To remove the radical on the left side of the equation, square both sides of the equation.

${\sqrt{x - 6}}^{2} = 5^{2}$

Step 4

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x - 6}$ as ${(x - 6)}^{\frac{1}{2}}$ .

${({(x - 6)}^{\frac{1}{2}})}^{2} = 5^{2}$

Simplify the left side.

Simplify ${({(x - 6)}^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${({(x - 6)}^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(x - 6)}^{\frac{1}{2} \cdot 2} = 5^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

${(x - 6)}^{\frac{1}{2} \cdot 2} = 5^{2}$

Rewrite the expression.

${(x - 6)}^{1} = 5^{2}$

Simplify.

$x - 6 = 5^{2}$

Simplify the right side.

Raise $5$ to the power of $2$ .

$x - 6 = 25$

Step 5

Move all terms not containing $x$ to the right side of the equation.

Add $6$ to both sides of the equation.

$x = 25 + 6$

Add $25$ and $6$ .

$x = 31$