Solve by Factoring w^2-2w=15

$w^{2} - 2 w = 15$

Step 1

Subtract $15$ from both sides of the equation.

$w^{2} - 2 w - 15 = 0$

Step 2

Factor $w^{2} - 2 w - 15$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 15$ and whose sum is $- 2$ .

$- 5, 3$

Write the factored form using these integers.

$(w - 5) (w + 3) = 0$

Step 3

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$w - 5 = 0$

$w + 3 = 0$

Step 4

Set $w - 5$ equal to $0$ and solve for $w$ .

Set $w - 5$ equal to $0$ .

$w - 5 = 0$

Add $5$ to both sides of the equation.

$w = 5$

Step 5

Set $w + 3$ equal to $0$ and solve for $w$ .

Set $w + 3$ equal to $0$ .

$w + 3 = 0$

Subtract $3$ from both sides of the equation.

$w = - 3$

Step 6

The final solution is all the values that make $(w - 5) (w + 3) = 0$ true.

$w = 5, - 3$

Solve by Factoring w^2-2w=15

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