Solve by Factoring x-13 square root of x+40=0

$x - 13 \sqrt{x} + 40 = 0$

Step 1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x}$ as $x^{\frac{1}{2}}$ .

$x - 13 x^{\frac{1}{2}} + 40 = 0$

Step 2

Rewrite $x$ as ${(x^{\frac{1}{2}})}^{2}$ .

${(x^{\frac{1}{2}})}^{2} - 13 x^{\frac{1}{2}} + 40 = 0$

Step 3

Let $u = x^{\frac{1}{2}}$ . Substitute $u$ for all occurrences of $x^{\frac{1}{2}}$ .

$u^{2} - 13 u + 40 = 0$

Step 4

Factor $u^{2} - 13 u + 40$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $40$ and whose sum is $- 13$ .

$- 8, - 5$

Write the factored form using these integers.

$(u - 8) (u - 5) = 0$

Step 5

Replace all occurrences of $u$ with $x^{\frac{1}{2}}$ .

$(x^{\frac{1}{2}} - 8) (x^{\frac{1}{2}} - 5) = 0$

Step 6

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x^{\frac{1}{2}} - 8 = 0$

$x^{\frac{1}{2}} - 5 = 0$

Step 7

Set $x^{\frac{1}{2}} - 8$ equal to $0$ and solve for $x$ .

Set $x^{\frac{1}{2}} - 8$ equal to $0$ .

$x^{\frac{1}{2}} - 8 = 0$

Solve $x^{\frac{1}{2}} - 8 = 0$ for $x$ .

Add $8$ to both sides of the equation.

$x^{\frac{1}{2}} = 8$

Raise each side of the equation to the power of $2$ to eliminate the fractional exponent on the left side.

${(x^{\frac{1}{2}})}^{2} = 8^{2}$

Simplify the exponent.

Simplify the left side.

Simplify ${(x^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${(x^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x^{\frac{1}{2} \cdot 2} = 8^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

$x^{\frac{1}{2} \cdot 2} = 8^{2}$

Rewrite the expression.

$x^{1} = 8^{2}$

Simplify.

$x = 8^{2}$

Simplify the right side.

Raise $8$ to the power of $2$ .

$x = 64$

Step 8

Set $x^{\frac{1}{2}} - 5$ equal to $0$ and solve for $x$ .

Set $x^{\frac{1}{2}} - 5$ equal to $0$ .

$x^{\frac{1}{2}} - 5 = 0$

Solve $x^{\frac{1}{2}} - 5 = 0$ for $x$ .

Add $5$ to both sides of the equation.

$x^{\frac{1}{2}} = 5$

Raise each side of the equation to the power of $2$ to eliminate the fractional exponent on the left side.

${(x^{\frac{1}{2}})}^{2} = 5^{2}$

Simplify the exponent.

Simplify the left side.

Simplify ${(x^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${(x^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x^{\frac{1}{2} \cdot 2} = 5^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

$x^{\frac{1}{2} \cdot 2} = 5^{2}$

Rewrite the expression.

$x^{1} = 5^{2}$

Simplify.

$x = 5^{2}$

Simplify the right side.

Raise $5$ to the power of $2$ .

$x = 25$

Step 9

The final solution is all the values that make $(x^{\frac{1}{2}} - 8) (x^{\frac{1}{2}} - 5) = 0$ true.

$x = 64, 25$

Solve by Factoring x-13 square root of x+40=0

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