Solve by Factoring x^2+10x+13=4

$x^{2} + 10 x + 13 = 4$

Step 1

Subtract $4$ from both sides of the equation.

$x^{2} + 10 x + 13 - 4 = 0$

Step 2

Subtract $4$ from $13$ .

$x^{2} + 10 x + 9 = 0$

Step 3

Factor $x^{2} + 10 x + 9$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $9$ and whose sum is $10$ .

$1, 9$

Write the factored form using these integers.

$(x + 1) (x + 9) = 0$

Step 4

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x + 1 = 0$

$x + 9 = 0$

Step 5

Set $x + 1$ equal to $0$ and solve for $x$ .

Set $x + 1$ equal to $0$ .

$x + 1 = 0$

Subtract $1$ from both sides of the equation.

$x = - 1$

Step 6

Set $x + 9$ equal to $0$ and solve for $x$ .

Set $x + 9$ equal to $0$ .

$x + 9 = 0$

Subtract $9$ from both sides of the equation.

$x = - 9$

Step 7

The final solution is all the values that make $(x + 1) (x + 9) = 0$ true.

$x = - 1, - 9$

Solve by Factoring x^2+10x+13=4

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