Solve by Factoring x^2-11x+19=-5

$x^{2} - 11 x + 19 = - 5$

Step 1

Add $5$ to both sides of the equation.

$x^{2} - 11 x + 19 + 5 = 0$

Step 2

Add $19$ and $5$ .

$x^{2} - 11 x + 24 = 0$

Step 3

Factor $x^{2} - 11 x + 24$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $24$ and whose sum is $- 11$ .

$- 8, - 3$

Write the factored form using these integers.

$(x - 8) (x - 3) = 0$

Step 4

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 8 = 0$

$x - 3 = 0$

Step 5

Set $x - 8$ equal to $0$ and solve for $x$ .

Set $x - 8$ equal to $0$ .

$x - 8 = 0$

Add $8$ to both sides of the equation.

$x = 8$

Step 6

Set $x - 3$ equal to $0$ and solve for $x$ .

Set $x - 3$ equal to $0$ .

$x - 3 = 0$

Add $3$ to both sides of the equation.

$x = 3$

Step 7

The final solution is all the values that make $(x - 8) (x - 3) = 0$ true.

$x = 8, 3$

Solve by Factoring x^2-11x+19=-5

Related Questions

Support LCMGCF.com by disabling your adblocker.