Solve by Factoring x^2+15=8x

$x^{2} + 15 = 8 x$

Step 1

Subtract $8 x$ from both sides of the equation.

$x^{2} + 15 - 8 x = 0$

Step 2

Factor $x^{2} + 15 - 8 x$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $15$ and whose sum is $- 8$ .

$- 5, - 3$

Write the factored form using these integers.

$(x - 5) (x - 3) = 0$

Step 3

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 5 = 0$

$x - 3 = 0$

Step 4

Set $x - 5$ equal to $0$ and solve for $x$ .

Set $x - 5$ equal to $0$ .

$x - 5 = 0$

Add $5$ to both sides of the equation.

$x = 5$

Step 5

Set $x - 3$ equal to $0$ and solve for $x$ .

Set $x - 3$ equal to $0$ .

$x - 3 = 0$

Add $3$ to both sides of the equation.

$x = 3$

Step 6

The final solution is all the values that make $(x - 5) (x - 3) = 0$ true.

$x = 5, 3$

Solve by Factoring x^2+15=8x

Related Questions

Support LCMGCF.com by disabling your adblocker.