Solve by Factoring x^2-16x=0

$x^{2} - 16 x = 0$

Factor $x$ out of $x^{2} - 16 x$ .

Factor $x$ out of $x^{2}$ .

$x \cdot x - 16 x = 0$

Factor $x$ out of $- 16 x$ .

$x \cdot x + x \cdot - 16 = 0$

Factor $x$ out of $x \cdot x + x \cdot - 16$ .

$x (x - 16) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x = 0$

$x - 16 = 0$

Set $x$ equal to $0$ .

$x = 0$

Set $x - 16$ equal to $0$ and solve for $x$ .

Set $x - 16$ equal to $0$ .

$x - 16 = 0$

Add $16$ to both sides of the equation.

$x = 16$

The final solution is all the values that make $x (x - 16) = 0$ true.

$x = 0, 16$