Solve by Factoring x^2+6x+3=3

$x^{2} + 6 x + 3 = 3$

Step 1

Subtract $3$ from both sides of the equation.

$x^{2} + 6 x + 3 - 3 = 0$

Step 2

Combine the opposite terms in $x^{2} + 6 x + 3 - 3$ .

Subtract $3$ from $3$ .

$x^{2} + 6 x + 0 = 0$

Add $x^{2} + 6 x$ and $0$ .

$x^{2} + 6 x = 0$

Step 3

Factor $x$ out of $x^{2} + 6 x$ .

Factor $x$ out of $x^{2}$ .

$x \cdot x + 6 x = 0$

Factor $x$ out of $6 x$ .

$x \cdot x + x \cdot 6 = 0$

Factor $x$ out of $x \cdot x + x \cdot 6$ .

$x (x + 6) = 0$

Step 4

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x = 0$

$x + 6 = 0$

Step 5

Set $x$ equal to $0$ .

$x = 0$

Step 6

Set $x + 6$ equal to $0$ and solve for $x$ .

Set $x + 6$ equal to $0$ .

$x + 6 = 0$

Subtract $6$ from both sides of the equation.

$x = - 6$

Step 7

The final solution is all the values that make $x (x + 6) = 0$ true.

$x = 0, - 6$