Solve by Factoring x^2+6x-40=0

$x^{2} + 6 x - 40 = 0$

Step 1

Factor $x^{2} + 6 x - 40$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 40$ and whose sum is $6$ .

$- 4, 10$

Write the factored form using these integers.

$(x - 4) (x + 10) = 0$

Step 2

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 4 = 0$

$x + 10 = 0$

Step 3

Set $x - 4$ equal to $0$ and solve for $x$ .

Set $x - 4$ equal to $0$ .

$x - 4 = 0$

Add $4$ to both sides of the equation.

$x = 4$

Step 4

Set $x + 10$ equal to $0$ and solve for $x$ .

Set $x + 10$ equal to $0$ .

$x + 10 = 0$

Subtract $10$ from both sides of the equation.

$x = - 10$

Step 5

The final solution is all the values that make $(x - 4) (x + 10) = 0$ true.

$x = 4, - 10$

Solve by Factoring x^2+6x-40=0

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