Solve by Factoring x^2 = square root of x

$x^{2} = \sqrt{x}$

Step 1

Subtract $\sqrt{x}$ from both sides of the equation.

$x^{2} - \sqrt{x} = 0$

Step 2

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x}$ as $x^{\frac{1}{2}}$ .

$x^{2} - x^{\frac{1}{2}} = 0$

Step 3

Factor $x^{\frac{1}{2}}$ out of $x^{2} - x^{\frac{1}{2}}$ .

Factor $x^{\frac{1}{2}}$ out of $x^{2}$ .

$x^{\frac{1}{2}} x^{\frac{3}{2}} - x^{\frac{1}{2}} = 0$

Factor $x^{\frac{1}{2}}$ out of $- x^{\frac{1}{2}}$ .

$x^{\frac{1}{2}} x^{\frac{3}{2}} + x^{\frac{1}{2}} \cdot - 1 = 0$

Factor $x^{\frac{1}{2}}$ out of $x^{\frac{1}{2}} x^{\frac{3}{2}} + x^{\frac{1}{2}} \cdot - 1$ .

$x^{\frac{1}{2}} (x^{\frac{3}{2}} - 1) = 0$

Step 4

Rewrite $x^{\frac{3}{2}}$ as ${(x^{\frac{1}{2}})}^{3}$ .

$x^{\frac{1}{2}} ({(x^{\frac{1}{2}})}^{3} - 1) = 0$

Step 5

Rewrite $1$ as $1^{3}$ .

$x^{\frac{1}{2}} ({(x^{\frac{1}{2}})}^{3} - 1^{3}) = 0$

Step 6

Since both terms are perfect cubes, factor using the difference of cubes formula, $a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$ where $a = x^{\frac{1}{2}}$ and $b = 1$ .

$x^{\frac{1}{2}} ((x^{\frac{1}{2}} - 1) ({(x^{\frac{1}{2}})}^{2} + x^{\frac{1}{2}} \cdot 1 + 1^{2})) = 0$

Step 7

Factor.

Simplify.

Multiply the exponents in ${(x^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x^{\frac{1}{2}} ((x^{\frac{1}{2}} - 1) (x^{\frac{1}{2} \cdot 2} + x^{\frac{1}{2}} \cdot 1 + 1^{2})) = 0$

Cancel the common factor of $2$ .

Cancel the common factor.

$x^{\frac{1}{2}} ((x^{\frac{1}{2}} - 1) (x^{\frac{1}{2} \cdot 2} + x^{\frac{1}{2}} \cdot 1 + 1^{2})) = 0$

Rewrite the expression.

$x^{\frac{1}{2}} ((x^{\frac{1}{2}} - 1) (x + x^{\frac{1}{2}} \cdot 1 + 1^{2})) = 0$

Simplify.

$x^{\frac{1}{2}} ((x^{\frac{1}{2}} - 1) (x + x^{\frac{1}{2}} \cdot 1 + 1^{2})) = 0$

Multiply $x^{\frac{1}{2}}$ by $1$ .

$x^{\frac{1}{2}} ((x^{\frac{1}{2}} - 1) (x + x^{\frac{1}{2}} + 1^{2})) = 0$

One to any power is one.

$x^{\frac{1}{2}} ((x^{\frac{1}{2}} - 1) (x + x^{\frac{1}{2}} + 1)) = 0$

Remove unnecessary parentheses.

$x^{\frac{1}{2}} (x^{\frac{1}{2}} - 1) (x + x^{\frac{1}{2}} + 1) = 0$

Step 8

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x^{\frac{1}{2}} = 0$

$x^{\frac{1}{2}} - 1 = 0$

$x + x^{\frac{1}{2}} + 1 = 0$

Step 9

Set $x^{\frac{1}{2}}$ equal to $0$ and solve for $x$ .

Set $x^{\frac{1}{2}}$ equal to $0$ .

$x^{\frac{1}{2}} = 0$

Solve $x^{\frac{1}{2}} = 0$ for $x$ .

Raise each side of the equation to the power of $2$ to eliminate the fractional exponent on the left side.

${(x^{\frac{1}{2}})}^{2} = 0^{2}$

Simplify the exponent.

Simplify the left side.

Simplify ${(x^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${(x^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x^{\frac{1}{2} \cdot 2} = 0^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

$x^{\frac{1}{2} \cdot 2} = 0^{2}$

Rewrite the expression.

$x^{1} = 0^{2}$

Simplify.

$x = 0^{2}$

Simplify the right side.

Raising $0$ to any positive power yields $0$ .

$x = 0$

Step 10

Set $x^{\frac{1}{2}} - 1$ equal to $0$ and solve for $x$ .

Set $x^{\frac{1}{2}} - 1$ equal to $0$ .

$x^{\frac{1}{2}} - 1 = 0$

Solve $x^{\frac{1}{2}} - 1 = 0$ for $x$ .

Add $1$ to both sides of the equation.

$x^{\frac{1}{2}} = 1$

Raise each side of the equation to the power of $2$ to eliminate the fractional exponent on the left side.

${(x^{\frac{1}{2}})}^{2} = 1^{2}$

Simplify the exponent.

Simplify the left side.

Simplify ${(x^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${(x^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x^{\frac{1}{2} \cdot 2} = 1^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

$x^{\frac{1}{2} \cdot 2} = 1^{2}$

Rewrite the expression.

$x^{1} = 1^{2}$

Simplify.

$x = 1^{2}$

Simplify the right side.

One to any power is one.

$x = 1$

Step 11

Set $x + x^{\frac{1}{2}} + 1$ equal to $0$ and solve for $x$ .

Set $x + x^{\frac{1}{2}} + 1$ equal to $0$ .

$x + x^{\frac{1}{2}} + 1 = 0$

Solve $x + x^{\frac{1}{2}} + 1 = 0$ for $x$ .

Find a common factor $x^{\frac{1}{2}}$ that is present in each term.

${(x^{\frac{1}{2}})}^{2} + x^{\frac{1}{2}} + 1$

Substitute $u$ for $x^{\frac{1}{2}}$ .

${(u)}^{2} + u + 1 = 0$

Solve for $u$ .

Remove parentheses.

$u^{2} + u + 1 = 0$

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Substitute the values $a = 1$ , $b = 1$ , and $c = 1$ into the quadratic formula and solve for $u$ .

$\frac{- 1 \pm \sqrt{1^{2} - 4 \cdot (1 \cdot 1)}}{2 \cdot 1}$

Simplify.

Simplify the numerator.

One to any power is one.

$u = \frac{- 1 \pm \sqrt{1 - 4 \cdot 1 \cdot 1}}{2 \cdot 1}$

Multiply $- 4 \cdot 1 \cdot 1$ .

Multiply $- 4$ by $1$ .

$u = \frac{- 1 \pm \sqrt{1 - 4 \cdot 1}}{2 \cdot 1}$

Multiply $- 4$ by $1$ .

$u = \frac{- 1 \pm \sqrt{1 - 4}}{2 \cdot 1}$

Subtract $4$ from $1$ .

$u = \frac{- 1 \pm \sqrt{- 3}}{2 \cdot 1}$

Rewrite $- 3$ as $- 1 (3)$ .

$u = \frac{- 1 \pm \sqrt{- 1 \cdot 3}}{2 \cdot 1}$

Rewrite $\sqrt{- 1 (3)}$ as $\sqrt{- 1} \cdot \sqrt{3}$ .

$u = \frac{- 1 \pm \sqrt{- 1} \cdot \sqrt{3}}{2 \cdot 1}$

Rewrite $\sqrt{- 1}$ as $i$ .

$u = \frac{- 1 \pm i \sqrt{3}}{2 \cdot 1}$

Multiply $2$ by $1$ .

$u = \frac{- 1 \pm i \sqrt{3}}{2}$

Simplify the expression to solve for the $+$ portion of the $\pm$ .

Simplify the numerator.

One to any power is one.

$u = \frac{- 1 \pm \sqrt{1 - 4 \cdot 1 \cdot 1}}{2 \cdot 1}$

Multiply $- 4 \cdot 1 \cdot 1$ .

Multiply $- 4$ by $1$ .

$u = \frac{- 1 \pm \sqrt{1 - 4 \cdot 1}}{2 \cdot 1}$

Multiply $- 4$ by $1$ .

$u = \frac{- 1 \pm \sqrt{1 - 4}}{2 \cdot 1}$

Subtract $4$ from $1$ .

$u = \frac{- 1 \pm \sqrt{- 3}}{2 \cdot 1}$

Rewrite $- 3$ as $- 1 (3)$ .

$u = \frac{- 1 \pm \sqrt{- 1 \cdot 3}}{2 \cdot 1}$

Rewrite $\sqrt{- 1 (3)}$ as $\sqrt{- 1} \cdot \sqrt{3}$ .

$u = \frac{- 1 \pm \sqrt{- 1} \cdot \sqrt{3}}{2 \cdot 1}$

Rewrite $\sqrt{- 1}$ as $i$ .

$u = \frac{- 1 \pm i \sqrt{3}}{2 \cdot 1}$

Multiply $2$ by $1$ .

$u = \frac{- 1 \pm i \sqrt{3}}{2}$

Change the $\pm$ to $+$ .

$u = \frac{- 1 + i \sqrt{3}}{2}$

Rewrite $- 1$ as $- 1 (1)$ .

$u = \frac{- 1 \cdot 1 + i \sqrt{3}}{2}$

Factor $- 1$ out of $i \sqrt{3}$ .

$u = \frac{- 1 \cdot 1 - (- i \sqrt{3})}{2}$

Factor $- 1$ out of $- 1 (1) - (- i \sqrt{3})$ .

$u = \frac{- 1 (1 - i \sqrt{3})}{2}$

Move the negative in front of the fraction.

$u = - \frac{1 - i \sqrt{3}}{2}$

Simplify the expression to solve for the $-$ portion of the $\pm$ .

Simplify the numerator.

One to any power is one.

$u = \frac{- 1 \pm \sqrt{1 - 4 \cdot 1 \cdot 1}}{2 \cdot 1}$

Multiply $- 4 \cdot 1 \cdot 1$ .

Multiply $- 4$ by $1$ .

$u = \frac{- 1 \pm \sqrt{1 - 4 \cdot 1}}{2 \cdot 1}$

Multiply $- 4$ by $1$ .

$u = \frac{- 1 \pm \sqrt{1 - 4}}{2 \cdot 1}$

Subtract $4$ from $1$ .

$u = \frac{- 1 \pm \sqrt{- 3}}{2 \cdot 1}$

Rewrite $- 3$ as $- 1 (3)$ .

$u = \frac{- 1 \pm \sqrt{- 1 \cdot 3}}{2 \cdot 1}$

Rewrite $\sqrt{- 1 (3)}$ as $\sqrt{- 1} \cdot \sqrt{3}$ .

$u = \frac{- 1 \pm \sqrt{- 1} \cdot \sqrt{3}}{2 \cdot 1}$

Rewrite $\sqrt{- 1}$ as $i$ .

$u = \frac{- 1 \pm i \sqrt{3}}{2 \cdot 1}$

Multiply $2$ by $1$ .

$u = \frac{- 1 \pm i \sqrt{3}}{2}$

Change the $\pm$ to $-$ .

$u = \frac{- 1 - i \sqrt{3}}{2}$

Rewrite $- 1$ as $- 1 (1)$ .

$u = \frac{- 1 \cdot 1 - i \sqrt{3}}{2}$

Factor $- 1$ out of $- i \sqrt{3}$ .

$u = \frac{- 1 \cdot 1 - (i \sqrt{3})}{2}$

Factor $- 1$ out of $- 1 (1) - (i \sqrt{3})$ .

$u = \frac{- 1 (1 + i \sqrt{3})}{2}$

Move the negative in front of the fraction.

$u = - \frac{1 + i \sqrt{3}}{2}$

The final answer is the combination of both solutions.

$u = - \frac{1 - i \sqrt{3}}{2}, - \frac{1 + i \sqrt{3}}{2}$

Substitute $x$ for $u$ .

$x^{\frac{1}{2}} = - \frac{1 - i \sqrt{3}}{2}, - \frac{1 + i \sqrt{3}}{2}$

Solve for $x^{\frac{1}{2}} = - \frac{1 - i \sqrt{3}}{2}$ for $x$ .

Raise each side of the equation to the power of $2$ to eliminate the fractional exponent on the left side.

${(x^{\frac{1}{2}})}^{2} = {(- \frac{1 - i \sqrt{3}}{2})}^{2}$

Simplify the exponent.

Simplify the left side.

Simplify ${(x^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${(x^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x^{\frac{1}{2} \cdot 2} = {(- \frac{1 - i \sqrt{3}}{2})}^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

$x^{\frac{1}{2} \cdot 2} = {(- \frac{1 - i \sqrt{3}}{2})}^{2}$

Rewrite the expression.

$x^{1} = {(- \frac{1 - i \sqrt{3}}{2})}^{2}$

Simplify.

$x = {(- \frac{1 - i \sqrt{3}}{2})}^{2}$

Simplify the right side.

Simplify ${(- \frac{1 - i \sqrt{3}}{2})}^{2}$ .

Use the power rule ${(a b)}^{n} = a^{n} b^{n}$ to distribute the exponent.

Apply the product rule to $- \frac{1 - i \sqrt{3}}{2}$ .

$x = {(- 1)}^{2} {(\frac{1 - i \sqrt{3}}{2})}^{2}$

Apply the product rule to $\frac{1 - i \sqrt{3}}{2}$ .

$x = {(- 1)}^{2} \frac{{(1 - i \sqrt{3})}^{2}}{2^{2}}$

Simplify the expression.

Raise $- 1$ to the power of $2$ .

$x = 1 \frac{{(1 - i \sqrt{3})}^{2}}{2^{2}}$

Multiply $\frac{{(1 - i \sqrt{3})}^{2}}{2^{2}}$ by $1$ .

$x = \frac{{(1 - i \sqrt{3})}^{2}}{2^{2}}$

Raise $2$ to the power of $2$ .

$x = \frac{{(1 - i \sqrt{3})}^{2}}{4}$

Rewrite ${(1 - i \sqrt{3})}^{2}$ as $(1 - i \sqrt{3}) (1 - i \sqrt{3})$ .

$x = \frac{(1 - i \sqrt{3}) (1 - i \sqrt{3})}{4}$

Expand $(1 - i \sqrt{3}) (1 - i \sqrt{3})$ using the FOIL Method.

Apply the distributive property.

$x = \frac{1 (1 - i \sqrt{3}) - i \sqrt{3} (1 - i \sqrt{3})}{4}$

Apply the distributive property.

$x = \frac{1 \cdot 1 + 1 (- i \sqrt{3}) - i \sqrt{3} (1 - i \sqrt{3})}{4}$

Apply the distributive property.

$x = \frac{1 \cdot 1 + 1 (- i \sqrt{3}) - i \sqrt{3} \cdot 1 - i \sqrt{3} (- i \sqrt{3})}{4}$

Simplify and combine like terms.

Simplify each term.

Multiply $1$ by $1$ .

$x = \frac{1 + 1 (- i \sqrt{3}) - i \sqrt{3} \cdot 1 - i \sqrt{3} (- i \sqrt{3})}{4}$

Multiply $- i \sqrt{3}$ by $1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} \cdot 1 - i \sqrt{3} (- i \sqrt{3})}{4}$

Multiply $- 1$ by $1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} - i \sqrt{3} (- i \sqrt{3})}{4}$

Multiply $- i \sqrt{3} (- i \sqrt{3})$ .

Multiply $- 1$ by $- 1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + 1 i \sqrt{3} (i \sqrt{3})}{4}$

Multiply $\sqrt{3}$ by $1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + \sqrt{3} i (i \sqrt{3})}{4}$

Raise $\sqrt{3}$ to the power of $1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + {\sqrt{3}}^{1} \sqrt{3} i i}{4}$

Raise $\sqrt{3}$ to the power of $1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + {\sqrt{3}}^{1} {\sqrt{3}}^{1} i i}{4}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + {\sqrt{3}}^{1 + 1} i i}{4}$

Add $1$ and $1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + {\sqrt{3}}^{2} i i}{4}$

Raise $i$ to the power of $1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + {\sqrt{3}}^{2} (i^{1} i)}{4}$

Raise $i$ to the power of $1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + {\sqrt{3}}^{2} (i^{1} i^{1})}{4}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + {\sqrt{3}}^{2} i^{1 + 1}}{4}$

Add $1$ and $1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + {\sqrt{3}}^{2} i^{2}}{4}$

Rewrite ${\sqrt{3}}^{2}$ as $3$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{3}$ as $3^{\frac{1}{2}}$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + {(3^{\frac{1}{2}})}^{2} i^{2}}{4}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + 3^{\frac{1}{2} \cdot 2} i^{2}}{4}$

Combine $\frac{1}{2}$ and $2$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + 3^{\frac{2}{2}} i^{2}}{4}$

Cancel the common factor of $2$ .

Cancel the common factor.

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + 3^{\frac{2}{2}} i^{2}}{4}$

Rewrite the expression.

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + 3^{1} i^{2}}{4}$

Evaluate the exponent.

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + 3 i^{2}}{4}$

Rewrite $i^{2}$ as $- 1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + 3 \cdot - 1}{4}$

Multiply $3$ by $- 1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} - 3}{4}$

Subtract $3$ from $1$ .

$x = \frac{- i \sqrt{3} - i \sqrt{3} - 2}{4}$

Subtract $i \sqrt{3}$ from $- i \sqrt{3}$ .

$x = \frac{- 2 i \sqrt{3} - 2}{4}$

Reorder $- 2 i \sqrt{3}$ and $- 2$ .

$x = \frac{- 2 - 2 i \sqrt{3}}{4}$

Cancel the common factor of $- 2 - 2 i \sqrt{3}$ and $4$ .

Factor $2$ out of $- 2$ .

$x = \frac{2 (- 1) - 2 i \sqrt{3}}{4}$

Factor $2$ out of $- 2 i \sqrt{3}$ .

$x = \frac{2 (- 1) + 2 (- i \sqrt{3})}{4}$

Factor $2$ out of $2 (- 1) + 2 (- i \sqrt{3})$ .

$x = \frac{2 (- 1 - i \sqrt{3})}{4}$

Cancel the common factors.

Factor $2$ out of $4$ .

$x = \frac{2 (- 1 - i \sqrt{3})}{2 \cdot 2}$

Cancel the common factor.

$x = \frac{2 (- 1 - i \sqrt{3})}{2 \cdot 2}$

Rewrite the expression.

$x = \frac{- 1 - i \sqrt{3}}{2}$

Rewrite $- 1$ as $- 1 (1)$ .

$x = \frac{- 1 (1) - i \sqrt{3}}{2}$

Factor $- 1$ out of $- i \sqrt{3}$ .

$x = \frac{- 1 (1) - (i \sqrt{3})}{2}$

Factor $- 1$ out of $- 1 (1) - (i \sqrt{3})$ .

$x = \frac{- 1 (1 + i \sqrt{3})}{2}$

Move the negative in front of the fraction.

$x = - \frac{1 + i \sqrt{3}}{2}$

Solve for $x^{\frac{1}{2}} = - \frac{1 + i \sqrt{3}}{2}$ for $x$ .

Raise each side of the equation to the power of $2$ to eliminate the fractional exponent on the left side.

${(x^{\frac{1}{2}})}^{2} = {(- \frac{1 + i \sqrt{3}}{2})}^{2}$

Simplify the exponent.

Simplify the left side.

Simplify ${(x^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${(x^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x^{\frac{1}{2} \cdot 2} = {(- \frac{1 + i \sqrt{3}}{2})}^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

$x^{\frac{1}{2} \cdot 2} = {(- \frac{1 + i \sqrt{3}}{2})}^{2}$

Rewrite the expression.

$x^{1} = {(- \frac{1 + i \sqrt{3}}{2})}^{2}$

Simplify.

$x = {(- \frac{1 + i \sqrt{3}}{2})}^{2}$

Simplify the right side.

Simplify ${(- \frac{1 + i \sqrt{3}}{2})}^{2}$ .

Use the power rule ${(a b)}^{n} = a^{n} b^{n}$ to distribute the exponent.

Apply the product rule to $- \frac{1 + i \sqrt{3}}{2}$ .

$x = {(- 1)}^{2} {(\frac{1 + i \sqrt{3}}{2})}^{2}$

Apply the product rule to $\frac{1 + i \sqrt{3}}{2}$ .

$x = {(- 1)}^{2} \frac{{(1 + i \sqrt{3})}^{2}}{2^{2}}$

Simplify the expression.

Raise $- 1$ to the power of $2$ .

$x = 1 \frac{{(1 + i \sqrt{3})}^{2}}{2^{2}}$

Multiply $\frac{{(1 + i \sqrt{3})}^{2}}{2^{2}}$ by $1$ .

$x = \frac{{(1 + i \sqrt{3})}^{2}}{2^{2}}$

Raise $2$ to the power of $2$ .

$x = \frac{{(1 + i \sqrt{3})}^{2}}{4}$

Rewrite ${(1 + i \sqrt{3})}^{2}$ as $(1 + i \sqrt{3}) (1 + i \sqrt{3})$ .

$x = \frac{(1 + i \sqrt{3}) (1 + i \sqrt{3})}{4}$

Expand $(1 + i \sqrt{3}) (1 + i \sqrt{3})$ using the FOIL Method.

Apply the distributive property.

$x = \frac{1 (1 + i \sqrt{3}) + i \sqrt{3} (1 + i \sqrt{3})}{4}$

Apply the distributive property.

$x = \frac{1 \cdot 1 + 1 (i \sqrt{3}) + i \sqrt{3} (1 + i \sqrt{3})}{4}$

Apply the distributive property.

$x = \frac{1 \cdot 1 + 1 (i \sqrt{3}) + i \sqrt{3} \cdot 1 + i \sqrt{3} (i \sqrt{3})}{4}$

Simplify and combine like terms.

Simplify each term.

Multiply $1$ by $1$ .

$x = \frac{1 + 1 (i \sqrt{3}) + i \sqrt{3} \cdot 1 + i \sqrt{3} (i \sqrt{3})}{4}$

Multiply $i \sqrt{3}$ by $1$ .

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} \cdot 1 + i \sqrt{3} (i \sqrt{3})}{4}$

Multiply $i$ by $1$ .

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} + i \sqrt{3} (i \sqrt{3})}{4}$

Multiply $i \sqrt{3} (i \sqrt{3})$ .

Raise $i$ to the power of $1$ .

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} + i^{1} i \sqrt{3} \sqrt{3}}{4}$

Raise $i$ to the power of $1$ .

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} + i^{1} i^{1} \sqrt{3} \sqrt{3}}{4}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} + i^{1 + 1} \sqrt{3} \sqrt{3}}{4}$

Add $1$ and $1$ .

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} + i^{2} \sqrt{3} \sqrt{3}}{4}$

Raise $\sqrt{3}$ to the power of $1$ .

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} + i^{2} ({\sqrt{3}}^{1} \sqrt{3})}{4}$

Raise $\sqrt{3}$ to the power of $1$ .

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} + i^{2} ({\sqrt{3}}^{1} {\sqrt{3}}^{1})}{4}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} + i^{2} {\sqrt{3}}^{1 + 1}}{4}$

Add $1$ and $1$ .

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} + i^{2} {\sqrt{3}}^{2}}{4}$

Rewrite $i^{2}$ as $- 1$ .

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} - 1 {\sqrt{3}}^{2}}{4}$

Rewrite ${\sqrt{3}}^{2}$ as $3$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{3}$ as $3^{\frac{1}{2}}$ .

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} - 1 {(3^{\frac{1}{2}})}^{2}}{4}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} - 1 \cdot 3^{\frac{1}{2} \cdot 2}}{4}$

Combine $\frac{1}{2}$ and $2$ .

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} - 1 \cdot 3^{\frac{2}{2}}}{4}$

Cancel the common factor of $2$ .

Cancel the common factor.

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} - 1 \cdot 3^{\frac{2}{2}}}{4}$

Rewrite the expression.

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} - 1 \cdot 3^{1}}{4}$

Evaluate the exponent.

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} - 1 \cdot 3}{4}$

Multiply $- 1$ by $3$ .

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} - 3}{4}$

Subtract $3$ from $1$ .

$x = \frac{i \sqrt{3} + i \sqrt{3} - 2}{4}$

Add $i \sqrt{3}$ and $i \sqrt{3}$ .

$x = \frac{2 i \sqrt{3} - 2}{4}$

Reorder $2 i \sqrt{3}$ and $- 2$ .

$x = \frac{- 2 + 2 i \sqrt{3}}{4}$

Cancel the common factor of $- 2 + 2 i \sqrt{3}$ and $4$ .

Factor $2$ out of $- 2$ .

$x = \frac{2 \cdot - 1 + 2 i \sqrt{3}}{4}$

Factor $2$ out of $2 i \sqrt{3}$ .

$x = \frac{2 \cdot - 1 + 2 (i \sqrt{3})}{4}$

Factor $2$ out of $2 \cdot - 1 + 2 (i \sqrt{3})$ .

$x = \frac{2 \cdot (- 1 + i \sqrt{3})}{4}$

Cancel the common factors.

Factor $2$ out of $4$ .

$x = \frac{2 \cdot (- 1 + i \sqrt{3})}{2 (2)}$

Cancel the common factor.

$x = \frac{2 \cdot (- 1 + i \sqrt{3})}{2 \cdot 2}$

Rewrite the expression.

$x = \frac{- 1 + i \sqrt{3}}{2}$

Rewrite $- 1$ as $- 1 (1)$ .

$x = \frac{- 1 (1) + i \sqrt{3}}{2}$

Factor $- 1$ out of $i \sqrt{3}$ .

$x = \frac{- 1 (1) - (- i \sqrt{3})}{2}$

Factor $- 1$ out of $- 1 (1) - (- i \sqrt{3})$ .

$x = \frac{- 1 (1 - i \sqrt{3})}{2}$

Move the negative in front of the fraction.

$x = - \frac{1 - i \sqrt{3}}{2}$

List all of the solutions.

$x = - \frac{1 + i \sqrt{3}}{2}, - \frac{1 - i \sqrt{3}}{2}$

Step 12

The final solution is all the values that make $x^{\frac{1}{2}} (x^{\frac{1}{2}} - 1) (x + x^{\frac{1}{2}} + 1) = 0$ true.

$x = 0, 1, - \frac{1 + i \sqrt{3}}{2}, - \frac{1 - i \sqrt{3}}{2}$

Solve by Factoring x^2 = square root of x

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