Solve by Factoring (x+2)/(x^2-9)+(x-3)/(x^2-2x-3)=(2x-3)/(x^2+4x+3)

$\frac{x + 2}{x^{2} - 9} + \frac{x - 3}{x^{2} - 2 x - 3} = \frac{2 x - 3}{x^{2} + 4 x + 3}$

Step 1

Subtract $\frac{2 x - 3}{x^{2} + 4 x + 3}$ from both sides of the equation.

$\frac{x + 2}{x^{2} - 9} + \frac{x - 3}{x^{2} - 2 x - 3} - \frac{2 x - 3}{x^{2} + 4 x + 3} = 0$

Step 2

Simplify $\frac{x + 2}{x^{2} - 9} + \frac{x - 3}{x^{2} - 2 x - 3} - \frac{2 x - 3}{x^{2} + 4 x + 3}$ .

Simplify each term.

Simplify the denominator.

Rewrite $9$ as $3^{2}$ .

$\frac{x + 2}{x^{2} - 3^{2}} + \frac{x - 3}{x^{2} - 2 x - 3} - \frac{2 x - 3}{x^{2} + 4 x + 3} = 0$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x$ and $b = 3$ .

$\frac{x + 2}{(x + 3) (x - 3)} + \frac{x - 3}{x^{2} - 2 x - 3} - \frac{2 x - 3}{x^{2} + 4 x + 3} = 0$

Factor $x^{2} - 2 x - 3$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 3$ and whose sum is $- 2$ .

$- 3, 1$

Write the factored form using these integers.

$\frac{x + 2}{(x + 3) (x - 3)} + \frac{x - 3}{(x - 3) (x + 1)} - \frac{2 x - 3}{x^{2} + 4 x + 3} = 0$

Cancel the common factor of $x - 3$ .

Cancel the common factor.

$\frac{x + 2}{(x + 3) (x - 3)} + \frac{x - 3}{(x - 3) (x + 1)} - \frac{2 x - 3}{x^{2} + 4 x + 3} = 0$

Rewrite the expression.

$\frac{x + 2}{(x + 3) (x - 3)} + \frac{1}{x + 1} - \frac{2 x - 3}{x^{2} + 4 x + 3} = 0$

Factor $x^{2} + 4 x + 3$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $3$ and whose sum is $4$ .

$1, 3$

Write the factored form using these integers.

$\frac{x + 2}{(x + 3) (x - 3)} + \frac{1}{x + 1} - \frac{2 x - 3}{(x + 1) (x + 3)} = 0$

Find the common denominator.

Multiply $\frac{x + 2}{(x + 3) (x - 3)}$ by $\frac{x + 1}{x + 1}$ .

$\frac{x + 2}{(x + 3) (x - 3)} \cdot \frac{x + 1}{x + 1} + \frac{1}{x + 1} - \frac{2 x - 3}{(x + 1) (x + 3)} = 0$

Multiply $\frac{x + 2}{(x + 3) (x - 3)}$ by $\frac{x + 1}{x + 1}$ .

$\frac{(x + 2) (x + 1)}{(x + 3) (x - 3) (x + 1)} + \frac{1}{x + 1} - \frac{2 x - 3}{(x + 1) (x + 3)} = 0$

Multiply $\frac{1}{x + 1}$ by $\frac{(x + 3) (x - 3)}{(x + 3) (x - 3)}$ .

$\frac{(x + 2) (x + 1)}{(x + 3) (x - 3) (x + 1)} + \frac{1}{x + 1} \cdot \frac{(x + 3) (x - 3)}{(x + 3) (x - 3)} - \frac{2 x - 3}{(x + 1) (x + 3)} = 0$

Multiply $\frac{1}{x + 1}$ by $\frac{(x + 3) (x - 3)}{(x + 3) (x - 3)}$ .

$\frac{(x + 2) (x + 1)}{(x + 3) (x - 3) (x + 1)} + \frac{(x + 3) (x - 3)}{(x + 1) ((x + 3) (x - 3))} - \frac{2 x - 3}{(x + 1) (x + 3)} = 0$

Multiply $\frac{2 x - 3}{(x + 1) (x + 3)}$ by $\frac{x - 3}{x - 3}$ .

$\frac{(x + 2) (x + 1)}{(x + 3) (x - 3) (x + 1)} + \frac{(x + 3) (x - 3)}{(x + 1) ((x + 3) (x - 3))} - (\frac{2 x - 3}{(x + 1) (x + 3)} \cdot \frac{x - 3}{x - 3}) = 0$

Multiply $\frac{2 x - 3}{(x + 1) (x + 3)}$ by $\frac{x - 3}{x - 3}$ .

$\frac{(x + 2) (x + 1)}{(x + 3) (x - 3) (x + 1)} + \frac{(x + 3) (x - 3)}{(x + 1) ((x + 3) (x - 3))} - \frac{(2 x - 3) (x - 3)}{(x + 1) (x + 3) (x - 3)} = 0$

Reorder the factors of $(x + 1) ((x + 3) (x - 3))$ .

$\frac{(x + 2) (x + 1)}{(x + 3) (x - 3) (x + 1)} + \frac{(x + 3) (x - 3)}{(x + 1) (x + 3) (x - 3)} - \frac{(2 x - 3) (x - 3)}{(x + 1) (x + 3) (x - 3)} = 0$

Combine the numerators over the common denominator.

$\frac{(x + 2) (x + 1) + (x + 3) (x - 3) - (2 x - 3) (x - 3)}{(x + 1) (x + 3) (x - 3)} = 0$

Simplify each term.

Expand $(x + 2) (x + 1)$ using the FOIL Method.

Apply the distributive property.

$\frac{x (x + 1) + 2 (x + 1) + (x + 3) (x - 3) - (2 x - 3) (x - 3)}{(x + 1) (x + 3) (x - 3)} = 0$

Apply the distributive property.

$\frac{x \cdot x + x \cdot 1 + 2 (x + 1) + (x + 3) (x - 3) - (2 x - 3) (x - 3)}{(x + 1) (x + 3) (x - 3)} = 0$

Apply the distributive property.

$\frac{x \cdot x + x \cdot 1 + 2 x + 2 \cdot 1 + (x + 3) (x - 3) - (2 x - 3) (x - 3)}{(x + 1) (x + 3) (x - 3)} = 0$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$\frac{x^{2} + x \cdot 1 + 2 x + 2 \cdot 1 + (x + 3) (x - 3) - (2 x - 3) (x - 3)}{(x + 1) (x + 3) (x - 3)} = 0$

Multiply $x$ by $1$ .

$\frac{x^{2} + x + 2 x + 2 \cdot 1 + (x + 3) (x - 3) - (2 x - 3) (x - 3)}{(x + 1) (x + 3) (x - 3)} = 0$

Multiply $2$ by $1$ .

$\frac{x^{2} + x + 2 x + 2 + (x + 3) (x - 3) - (2 x - 3) (x - 3)}{(x + 1) (x + 3) (x - 3)} = 0$

Add $x$ and $2 x$ .

$\frac{x^{2} + 3 x + 2 + (x + 3) (x - 3) - (2 x - 3) (x - 3)}{(x + 1) (x + 3) (x - 3)} = 0$

Expand $(x + 3) (x - 3)$ using the FOIL Method.

Apply the distributive property.

$\frac{x^{2} + 3 x + 2 + x (x - 3) + 3 (x - 3) - (2 x - 3) (x - 3)}{(x + 1) (x + 3) (x - 3)} = 0$

Apply the distributive property.

$\frac{x^{2} + 3 x + 2 + x \cdot x + x \cdot - 3 + 3 (x - 3) - (2 x - 3) (x - 3)}{(x + 1) (x + 3) (x - 3)} = 0$

Apply the distributive property.

$\frac{x^{2} + 3 x + 2 + x \cdot x + x \cdot - 3 + 3 x + 3 \cdot - 3 - (2 x - 3) (x - 3)}{(x + 1) (x + 3) (x - 3)} = 0$

Combine the opposite terms in $x \cdot x + x \cdot - 3 + 3 x + 3 \cdot - 3$ .

Reorder the factors in the terms $x \cdot - 3$ and $3 x$ .

$\frac{x^{2} + 3 x + 2 + x \cdot x - 3 x + 3 x + 3 \cdot - 3 - (2 x - 3) (x - 3)}{(x + 1) (x + 3) (x - 3)} = 0$

Add $- 3 x$ and $3 x$ .

$\frac{x^{2} + 3 x + 2 + x \cdot x + 0 + 3 \cdot - 3 - (2 x - 3) (x - 3)}{(x + 1) (x + 3) (x - 3)} = 0$

Add $x \cdot x$ and $0$ .

$\frac{x^{2} + 3 x + 2 + x \cdot x + 3 \cdot - 3 - (2 x - 3) (x - 3)}{(x + 1) (x + 3) (x - 3)} = 0$

Simplify each term.

Multiply $x$ by $x$ .

$\frac{x^{2} + 3 x + 2 + x^{2} + 3 \cdot - 3 - (2 x - 3) (x - 3)}{(x + 1) (x + 3) (x - 3)} = 0$

Multiply $3$ by $- 3$ .

$\frac{x^{2} + 3 x + 2 + x^{2} - 9 - (2 x - 3) (x - 3)}{(x + 1) (x + 3) (x - 3)} = 0$

Apply the distributive property.

$\frac{x^{2} + 3 x + 2 + x^{2} - 9 + (- (2 x) - - 3) (x - 3)}{(x + 1) (x + 3) (x - 3)} = 0$

Multiply $2$ by $- 1$ .

$\frac{x^{2} + 3 x + 2 + x^{2} - 9 + (- 2 x - - 3) (x - 3)}{(x + 1) (x + 3) (x - 3)} = 0$

Multiply $- 1$ by $- 3$ .

$\frac{x^{2} + 3 x + 2 + x^{2} - 9 + (- 2 x + 3) (x - 3)}{(x + 1) (x + 3) (x - 3)} = 0$

Expand $(- 2 x + 3) (x - 3)$ using the FOIL Method.

Apply the distributive property.

$\frac{x^{2} + 3 x + 2 + x^{2} - 9 - 2 x (x - 3) + 3 (x - 3)}{(x + 1) (x + 3) (x - 3)} = 0$

Apply the distributive property.

$\frac{x^{2} + 3 x + 2 + x^{2} - 9 - 2 x \cdot x - 2 x \cdot - 3 + 3 (x - 3)}{(x + 1) (x + 3) (x - 3)} = 0$

Apply the distributive property.

$\frac{x^{2} + 3 x + 2 + x^{2} - 9 - 2 x \cdot x - 2 x \cdot - 3 + 3 x + 3 \cdot - 3}{(x + 1) (x + 3) (x - 3)} = 0$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ by adding the exponents.

Move $x$ .

$\frac{x^{2} + 3 x + 2 + x^{2} - 9 - 2 (x \cdot x) - 2 x \cdot - 3 + 3 x + 3 \cdot - 3}{(x + 1) (x + 3) (x - 3)} = 0$

Multiply $x$ by $x$ .

$\frac{x^{2} + 3 x + 2 + x^{2} - 9 - 2 x^{2} - 2 x \cdot - 3 + 3 x + 3 \cdot - 3}{(x + 1) (x + 3) (x - 3)} = 0$

Multiply $- 3$ by $- 2$ .

$\frac{x^{2} + 3 x + 2 + x^{2} - 9 - 2 x^{2} + 6 x + 3 x + 3 \cdot - 3}{(x + 1) (x + 3) (x - 3)} = 0$

Multiply $3$ by $- 3$ .

$\frac{x^{2} + 3 x + 2 + x^{2} - 9 - 2 x^{2} + 6 x + 3 x - 9}{(x + 1) (x + 3) (x - 3)} = 0$

Add $6 x$ and $3 x$ .

$\frac{x^{2} + 3 x + 2 + x^{2} - 9 - 2 x^{2} + 9 x - 9}{(x + 1) (x + 3) (x - 3)} = 0$

Add $x^{2}$ and $x^{2}$ .

$\frac{2 x^{2} + 3 x + 2 - 9 - 2 x^{2} + 9 x - 9}{(x + 1) (x + 3) (x - 3)} = 0$

Combine the opposite terms in $2 x^{2} + 3 x + 2 - 9 - 2 x^{2} + 9 x - 9$ .

Subtract $2 x^{2}$ from $2 x^{2}$ .

$\frac{3 x + 2 - 9 + 0 + 9 x - 9}{(x + 1) (x + 3) (x - 3)} = 0$

Add $3 x + 2 - 9$ and $0$ .

$\frac{3 x + 2 - 9 + 9 x - 9}{(x + 1) (x + 3) (x - 3)} = 0$

Add $3 x$ and $9 x$ .

$\frac{12 x + 2 - 9 - 9}{(x + 1) (x + 3) (x - 3)} = 0$

Subtract $9$ from $2$ .

$\frac{12 x - 7 - 9}{(x + 1) (x + 3) (x - 3)} = 0$

Subtract $9$ from $- 7$ .

$\frac{12 x - 16}{(x + 1) (x + 3) (x - 3)} = 0$

Factor $4$ out of $12 x - 16$ .

Factor $4$ out of $12 x$ .

$\frac{4 (3 x) - 16}{(x + 1) (x + 3) (x - 3)} = 0$

Factor $4$ out of $- 16$ .

$\frac{4 (3 x) + 4 (- 4)}{(x + 1) (x + 3) (x - 3)} = 0$

Factor $4$ out of $4 (3 x) + 4 (- 4)$ .

$\frac{4 (3 x - 4)}{(x + 1) (x + 3) (x - 3)} = 0$

Step 3

Set the numerator equal to zero.

$4 (3 x - 4) = 0$

Step 4

Solve the equation for $x$ .

Divide each term in $4 (3 x - 4) = 0$ by $4$ and simplify.

Divide each term in $4 (3 x - 4) = 0$ by $4$ .

$\frac{4 (3 x - 4)}{4} = \frac{0}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 (3 x - 4)}{4} = \frac{0}{4}$

Divide $3 x - 4$ by $1$ .

$3 x - 4 = \frac{0}{4}$

Simplify the right side.

Divide $0$ by $4$ .

$3 x - 4 = 0$

Add $4$ to both sides of the equation.

$3 x = 4$

Divide each term in $3 x = 4$ by $3$ and simplify.

Divide each term in $3 x = 4$ by $3$ .

$\frac{3 x}{3} = \frac{4}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{4}{3}$

Divide $x$ by $1$ .

$x = \frac{4}{3}$

Solve by Factoring (x+2)/(x^2-9)+(x-3)/(x^2-2x-3)=(2x-3)/(x^2+4x+3)

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