Solve by Factoring x^2-x-8=-3x

$x^{2} - x - 8 = - 3 x$

Step 1

Add $3 x$ to both sides of the equation.

$x^{2} - x - 8 + 3 x = 0$

Step 2

Add $- x$ and $3 x$ .

$x^{2} + 2 x - 8 = 0$

Step 3

Factor $x^{2} + 2 x - 8$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 8$ and whose sum is $2$ .

$- 2, 4$

Write the factored form using these integers.

$(x - 2) (x + 4) = 0$

Step 4

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 2 = 0$

$x + 4 = 0$

Step 5

Set $x - 2$ equal to $0$ and solve for $x$ .

Set $x - 2$ equal to $0$ .

$x - 2 = 0$

Add $2$ to both sides of the equation.

$x = 2$

Step 6

Set $x + 4$ equal to $0$ and solve for $x$ .

Set $x + 4$ equal to $0$ .

$x + 4 = 0$

Subtract $4$ from both sides of the equation.

$x = - 4$

Step 7

The final solution is all the values that make $(x - 2) (x + 4) = 0$ true.

$x = 2, - 4$

Solve by Factoring x^2-x-8=-3x

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