Solve by Factoring x^3+10x^2+24x=0

$x^{3} + 10 x^{2} + 24 x = 0$

Step 1

Factor $x$ out of $x^{3} + 10 x^{2} + 24 x$ .

Factor $x$ out of $x^{3}$ .

$x \cdot x^{2} + 10 x^{2} + 24 x = 0$

Factor $x$ out of $10 x^{2}$ .

$x \cdot x^{2} + x (10 x) + 24 x = 0$

Factor $x$ out of $24 x$ .

$x \cdot x^{2} + x (10 x) + x \cdot 24 = 0$

Factor $x$ out of $x \cdot x^{2} + x (10 x)$ .

$x (x^{2} + 10 x) + x \cdot 24 = 0$

Factor $x$ out of $x (x^{2} + 10 x) + x \cdot 24$ .

$x (x^{2} + 10 x + 24) = 0$

Step 2

Factor.

Factor $x^{2} + 10 x + 24$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $24$ and whose sum is $10$ .

$4, 6$

Write the factored form using these integers.

$x ((x + 4) (x + 6)) = 0$

Remove unnecessary parentheses.

$x (x + 4) (x + 6) = 0$

Step 3

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x = 0$

$x + 4 = 0$

$x + 6 = 0$

Step 4

Set $x$ equal to $0$ .

$x = 0$

Step 5

Set $x + 4$ equal to $0$ and solve for $x$ .

Set $x + 4$ equal to $0$ .

$x + 4 = 0$

Subtract $4$ from both sides of the equation.

$x = - 4$

Step 6

Set $x + 6$ equal to $0$ and solve for $x$ .

Set $x + 6$ equal to $0$ .

$x + 6 = 0$

Subtract $6$ from both sides of the equation.

$x = - 6$

Step 7

The final solution is all the values that make $x (x + 4) (x + 6) = 0$ true.

$x = 0, - 4, - 6$

Solve by Factoring x^3+10x^2+24x=0

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