Solve by Factoring x^4+3=13-9x^4

$x^{4} + 3 = 13 - 9 x^{4}$

Step 1

Move all the expressions to the left side of the equation.

Subtract $13$ from both sides of the equation.

$x^{4} + 3 - 13 = - 9 x^{4}$

Add $9 x^{4}$ to both sides of the equation.

$x^{4} + 3 - 13 + 9 x^{4} = 0$

Step 2

Simplify $x^{4} + 3 - 13 + 9 x^{4}$ .

Add $x^{4}$ and $9 x^{4}$ .

$10 x^{4} + 3 - 13 = 0$

Subtract $13$ from $3$ .

$10 x^{4} - 10 = 0$

Step 3

Factor $10$ out of $10 x^{4} - 10$ .

Factor $10$ out of $10 x^{4}$ .

$10 (x^{4}) - 10 = 0$

Factor $10$ out of $- 10$ .

$10 (x^{4}) + 10 (- 1) = 0$

Factor $10$ out of $10 (x^{4}) + 10 (- 1)$ .

$10 (x^{4} - 1) = 0$

Step 4

Rewrite $x^{4}$ as ${(x^{2})}^{2}$ .

$10 ({(x^{2})}^{2} - 1) = 0$

Step 5

Rewrite $1$ as $1^{2}$ .

$10 ({(x^{2})}^{2} - 1^{2}) = 0$

Step 6

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x^{2}$ and $b = 1$ .

$10 ((x^{2} + 1) (x^{2} - 1)) = 0$

Step 7

Factor.

Simplify.

Rewrite $1$ as $1^{2}$ .

$10 ((x^{2} + 1) (x^{2} - 1^{2})) = 0$

Factor.

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x$ and $b = 1$ .

$10 ((x^{2} + 1) ((x + 1) (x - 1))) = 0$

Remove unnecessary parentheses.

$10 ((x^{2} + 1) (x + 1) (x - 1)) = 0$

Remove unnecessary parentheses.

$10 (x^{2} + 1) (x + 1) (x - 1) = 0$

Step 8

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x^{2} + 1 = 0$

$x + 1 = 0$

$x - 1 = 0$

Step 9

Set $x^{2} + 1$ equal to $0$ and solve for $x$ .

Set $x^{2} + 1$ equal to $0$ .

$x^{2} + 1 = 0$

Solve $x^{2} + 1 = 0$ for $x$ .

Subtract $1$ from both sides of the equation.

$x^{2} = - 1$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{- 1}$

Rewrite $\sqrt{- 1}$ as $i$ .

$x = \pm i$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x = i$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - i$

The complete solution is the result of both the positive and negative portions of the solution.

$x = i, - i$

Step 10

Set $x + 1$ equal to $0$ and solve for $x$ .

Set $x + 1$ equal to $0$ .

$x + 1 = 0$

Subtract $1$ from both sides of the equation.

$x = - 1$

Step 11

Set $x - 1$ equal to $0$ and solve for $x$ .

Set $x - 1$ equal to $0$ .

$x - 1 = 0$

Add $1$ to both sides of the equation.

$x = 1$

Step 12

The final solution is all the values that make $10 (x^{2} + 1) (x + 1) (x - 1) = 0$ true.

$x = i, - i, - 1, 1$

Solve by Factoring x^4+3=13-9x^4

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