Solve by Factoring (x+4)/(x+3)=1/(x+3)

$\frac{x + 4}{x + 3} = \frac{1}{x + 3}$

Step 1

Subtract $\frac{1}{x + 3}$ from both sides of the equation.

$\frac{x + 4}{x + 3} - \frac{1}{x + 3} = 0$

Step 2

Simplify $\frac{x + 4}{x + 3} - \frac{1}{x + 3}$ .

Combine the numerators over the common denominator.

$\frac{x + 4 - 1}{x + 3} = 0$

Subtract $1$ from $4$ .

$\frac{x + 3}{x + 3} = 0$

Cancel the common factor of $x + 3$ .

Cancel the common factor.

$\frac{x + 3}{x + 3} = 0$

Rewrite the expression.

$1 = 0$

Step 3

Since $1 \neq 0$ , there are no solutions.

No solution