Solve by Factoring x+4/x=-5

$x + \frac{4}{x} = - 5$

Step 1

Add $5$ to both sides of the equation.

$x + \frac{4}{x} + 5 = 0$

Step 2

To write $x$ as a fraction with a common denominator, multiply by $\frac{x}{x}$ .

$\frac{x \cdot x}{x} + \frac{4}{x} + 5 = 0$

Step 3

Combine the numerators over the common denominator.

$\frac{x \cdot x + 4}{x} + 5 = 0$

Step 4

Multiply $x$ by $x$ .

$\frac{x^{2} + 4}{x} + 5 = 0$

Step 5

To write $5$ as a fraction with a common denominator, multiply by $\frac{x}{x}$ .

$\frac{x^{2} + 4}{x} + \frac{5 x}{x} = 0$

Step 6

Combine the numerators over the common denominator.

$\frac{x^{2} + 4 + 5 x}{x} = 0$

Step 7

Factor $x^{2} + 4 + 5 x$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $4$ and whose sum is $5$ .

$1, 4$

Write the factored form using these integers.

$\frac{(x + 1) (x + 4)}{x} = 0$

Step 8

Set the numerator equal to zero.

$(x + 1) (x + 4) = 0$

Step 9

Solve the equation for $x$ .

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x + 1 = 0$

$x + 4 = 0$

Set $x + 1$ equal to $0$ and solve for $x$ .

Set $x + 1$ equal to $0$ .

$x + 1 = 0$

Subtract $1$ from both sides of the equation.

$x = - 1$

Set $x + 4$ equal to $0$ and solve for $x$ .

Set $x + 4$ equal to $0$ .

$x + 4 = 0$

Subtract $4$ from both sides of the equation.

$x = - 4$

The final solution is all the values that make $(x + 1) (x + 4) = 0$ true.

$x = - 1, - 4$

Solve by Factoring x+4/x=-5

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