Solve by Factoring x = square root of 5x+14

$x = \sqrt{5 x + 14}$

Step 1

Subtract $\sqrt{5 x + 14}$ from both sides of the equation.

$x - \sqrt{5 x + 14} = 0$

Step 2

Subtract $x$ from both sides of the equation.

$- \sqrt{5 x + 14} = - x$

Step 3

To remove the radical on the left side of the equation, square both sides of the equation.

${(- \sqrt{5 x + 14})}^{2} = {(- x)}^{2}$

Step 4

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{5 x + 14}$ as ${(5 x + 14)}^{\frac{1}{2}}$ .

${(- {(5 x + 14)}^{\frac{1}{2}})}^{2} = {(- x)}^{2}$

Simplify the left side.

Simplify ${(- {(5 x + 14)}^{\frac{1}{2}})}^{2}$ .

Apply the product rule to $- {(5 x + 14)}^{\frac{1}{2}}$ .

${(- 1)}^{2} {({(5 x + 14)}^{\frac{1}{2}})}^{2} = {(- x)}^{2}$

Raise $- 1$ to the power of $2$ .

$1 {({(5 x + 14)}^{\frac{1}{2}})}^{2} = {(- x)}^{2}$

Multiply ${({(5 x + 14)}^{\frac{1}{2}})}^{2}$ by $1$ .

${({(5 x + 14)}^{\frac{1}{2}})}^{2} = {(- x)}^{2}$

Multiply the exponents in ${({(5 x + 14)}^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(5 x + 14)}^{\frac{1}{2} \cdot 2} = {(- x)}^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

${(5 x + 14)}^{\frac{1}{2} \cdot 2} = {(- x)}^{2}$

Rewrite the expression.

${(5 x + 14)}^{1} = {(- x)}^{2}$

Simplify.

$5 x + 14 = {(- x)}^{2}$

Simplify the right side.

Simplify ${(- x)}^{2}$ .

Apply the product rule to $- x$ .

$5 x + 14 = {(- 1)}^{2} x^{2}$

Raise $- 1$ to the power of $2$ .

$5 x + 14 = 1 x^{2}$

Multiply $x^{2}$ by $1$ .

$5 x + 14 = x^{2}$

Step 5

Solve for $x$ .

Subtract $x^{2}$ from both sides of the equation.

$5 x + 14 - x^{2} = 0$

Factor the left side of the equation.

Factor $- 1$ out of $5 x + 14 - x^{2}$ .

Reorder the expression.

Move $14$ .

$5 x - x^{2} + 14 = 0$

Reorder $5 x$ and $- x^{2}$ .

$- x^{2} + 5 x + 14 = 0$

Factor $- 1$ out of $- x^{2}$ .

$- (x^{2}) + 5 x + 14 = 0$

Factor $- 1$ out of $5 x$ .

$- (x^{2}) - (- 5 x) + 14 = 0$

Rewrite $14$ as $- 1 (- 14)$ .

$- (x^{2}) - (- 5 x) - 1 \cdot - 14 = 0$

Factor $- 1$ out of $- (x^{2}) - (- 5 x)$ .

$- (x^{2} - 5 x) - 1 \cdot - 14 = 0$

Factor $- 1$ out of $- (x^{2} - 5 x) - 1 (- 14)$ .

$- (x^{2} - 5 x - 14) = 0$

Factor.

Factor $x^{2} - 5 x - 14$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 14$ and whose sum is $- 5$ .

$- 7, 2$

Write the factored form using these integers.

$- ((x - 7) (x + 2)) = 0$

Remove unnecessary parentheses.

$- (x - 7) (x + 2) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 7 = 0$

$x + 2 = 0$

Set $x - 7$ equal to $0$ and solve for $x$ .

Set $x - 7$ equal to $0$ .

$x - 7 = 0$

Add $7$ to both sides of the equation.

$x = 7$

Set $x + 2$ equal to $0$ and solve for $x$ .

Set $x + 2$ equal to $0$ .

$x + 2 = 0$

Subtract $2$ from both sides of the equation.

$x = - 2$

The final solution is all the values that make $- (x - 7) (x + 2) = 0$ true.

$x = 7, - 2$

Step 6

Exclude the solutions that do not make $x - \sqrt{5 x + 14} = 0$ true.

$x = 7$

Solve by Factoring x = square root of 5x+14

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