Solve by Factoring x- square root of 6x=12

$x - \sqrt{6 x} = 12$

Step 1

Subtract $12$ from both sides of the equation.

$x - \sqrt{6 x} - 12 = 0$

Step 2

Move all terms not containing $- \sqrt{6 x}$ to the right side of the equation.

Subtract $x$ from both sides of the equation.

$- \sqrt{6 x} - 12 = - x$

Add $12$ to both sides of the equation.

$- \sqrt{6 x} = - x + 12$

Step 3

To remove the radical on the left side of the equation, square both sides of the equation.

${(- \sqrt{6 x})}^{2} = {(- x + 12)}^{2}$

Step 4

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{6 x}$ as ${(6 x)}^{\frac{1}{2}}$ .

${(- {(6 x)}^{\frac{1}{2}})}^{2} = {(- x + 12)}^{2}$

Simplify the left side.

Simplify ${(- {(6 x)}^{\frac{1}{2}})}^{2}$ .

Apply the product rule to $6 x$ .

${(- (6^{\frac{1}{2}} x^{\frac{1}{2}}))}^{2} = {(- x + 12)}^{2}$

Use the power rule ${(a b)}^{n} = a^{n} b^{n}$ to distribute the exponent.

Apply the product rule to $- 6^{\frac{1}{2}} x^{\frac{1}{2}}$ .

${(- 6^{\frac{1}{2}})}^{2} {(x^{\frac{1}{2}})}^{2} = {(- x + 12)}^{2}$

Apply the product rule to $- 6^{\frac{1}{2}}$ .

${(- 1)}^{2} {(6^{\frac{1}{2}})}^{2} {(x^{\frac{1}{2}})}^{2} = {(- x + 12)}^{2}$

Raise $- 1$ to the power of $2$ .

$1 {(6^{\frac{1}{2}})}^{2} {(x^{\frac{1}{2}})}^{2} = {(- x + 12)}^{2}$

Multiply ${(6^{\frac{1}{2}})}^{2}$ by $1$ .

${(6^{\frac{1}{2}})}^{2} {(x^{\frac{1}{2}})}^{2} = {(- x + 12)}^{2}$

Multiply the exponents in ${(6^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$6^{\frac{1}{2} \cdot 2} {(x^{\frac{1}{2}})}^{2} = {(- x + 12)}^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

$6^{\frac{1}{2} \cdot 2} {(x^{\frac{1}{2}})}^{2} = {(- x + 12)}^{2}$

Rewrite the expression.

$6^{1} {(x^{\frac{1}{2}})}^{2} = {(- x + 12)}^{2}$

Evaluate the exponent.

$6 {(x^{\frac{1}{2}})}^{2} = {(- x + 12)}^{2}$

Multiply the exponents in ${(x^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$6 x^{\frac{1}{2} \cdot 2} = {(- x + 12)}^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

$6 x^{\frac{1}{2} \cdot 2} = {(- x + 12)}^{2}$

Rewrite the expression.

$6 x^{1} = {(- x + 12)}^{2}$

Simplify.

$6 x = {(- x + 12)}^{2}$

Simplify the right side.

Simplify ${(- x + 12)}^{2}$ .

Rewrite ${(- x + 12)}^{2}$ as $(- x + 12) (- x + 12)$ .

$6 x = (- x + 12) (- x + 12)$

Expand $(- x + 12) (- x + 12)$ using the FOIL Method.

Apply the distributive property.

$6 x = - x (- x + 12) + 12 (- x + 12)$

Apply the distributive property.

$6 x = - x (- x) - x \cdot 12 + 12 (- x + 12)$

Apply the distributive property.

$6 x = - x (- x) - x \cdot 12 + 12 (- x) + 12 \cdot 12$

Simplify and combine like terms.

Simplify each term.

Rewrite using the commutative property of multiplication.

$6 x = - 1 \cdot - 1 x \cdot x - x \cdot 12 + 12 (- x) + 12 \cdot 12$

Multiply $x$ by $x$ by adding the exponents.

Move $x$ .

$6 x = - 1 \cdot - 1 (x \cdot x) - x \cdot 12 + 12 (- x) + 12 \cdot 12$

Multiply $x$ by $x$ .

$6 x = - 1 \cdot - 1 x^{2} - x \cdot 12 + 12 (- x) + 12 \cdot 12$

Multiply $- 1$ by $- 1$ .

$6 x = 1 x^{2} - x \cdot 12 + 12 (- x) + 12 \cdot 12$

Multiply $x^{2}$ by $1$ .

$6 x = x^{2} - x \cdot 12 + 12 (- x) + 12 \cdot 12$

Multiply $12$ by $- 1$ .

$6 x = x^{2} - 12 x + 12 (- x) + 12 \cdot 12$

Multiply $- 1$ by $12$ .

$6 x = x^{2} - 12 x - 12 x + 12 \cdot 12$

Multiply $12$ by $12$ .

$6 x = x^{2} - 12 x - 12 x + 144$

Subtract $12 x$ from $- 12 x$ .

$6 x = x^{2} - 24 x + 144$

Step 5

Solve for $x$ .

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$x^{2} - 24 x + 144 = 6 x$

Move all terms containing $x$ to the left side of the equation.

Subtract $6 x$ from both sides of the equation.

$x^{2} - 24 x + 144 - 6 x = 0$

Subtract $6 x$ from $- 24 x$ .

$x^{2} - 30 x + 144 = 0$

Factor $x^{2} - 30 x + 144$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $144$ and whose sum is $- 30$ .

$- 24, - 6$

Write the factored form using these integers.

$(x - 24) (x - 6) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 24 = 0$

$x - 6 = 0$

Set $x - 24$ equal to $0$ and solve for $x$ .

Set $x - 24$ equal to $0$ .

$x - 24 = 0$

Add $24$ to both sides of the equation.

$x = 24$

Set $x - 6$ equal to $0$ and solve for $x$ .

Set $x - 6$ equal to $0$ .

$x - 6 = 0$

Add $6$ to both sides of the equation.

$x = 6$

The final solution is all the values that make $(x - 24) (x - 6) = 0$ true.

$x = 24, 6$

Step 6

Exclude the solutions that do not make $x - \sqrt{6 x} - 12 = 0$ true.

$x = 24$

Solve by Factoring x- square root of 6x=12

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