Solve by Factoring x=x^2

$x = x^{2}$

Subtract $x^{2}$ from both sides of the equation.

$x - x^{2} = 0$

Factor $x$ out of $x - x^{2}$ .

Factor $x$ out of $x^{1}$ .

$x \cdot 1 - x^{2} = 0$

Factor $x$ out of $- x^{2}$ .

$x \cdot 1 + x (- x) = 0$

Factor $x$ out of $x \cdot 1 + x (- x)$ .

$x (1 - x) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x = 0$

$1 - x = 0$

Set $x$ equal to $0$ .

$x = 0$

Set $1 - x$ equal to $0$ and solve for $x$ .

Set $1 - x$ equal to $0$ .

$1 - x = 0$

Solve $1 - x = 0$ for $x$ .

Subtract $1$ from both sides of the equation.

$- x = - 1$

Divide each term in $- x = - 1$ by $- 1$ and simplify.

Divide each term in $- x = - 1$ by $- 1$ .

$\frac{- x}{- 1} = \frac{- 1}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{- 1}{- 1}$

Divide $x$ by $1$ .

$x = \frac{- 1}{- 1}$

Simplify the right side.

Divide $- 1$ by $- 1$ .

$x = 1$

The final solution is all the values that make $x (1 - x) = 0$ true.

$x = 0, 1$