Solve by Factoring y^2-16y+60=0

$y^{2} - 16 y + 60 = 0$

Step 1

Factor $y^{2} - 16 y + 60$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $60$ and whose sum is $- 16$ .

$- 10, - 6$

Write the factored form using these integers.

$(y - 10) (y - 6) = 0$

Step 2

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$y - 10 = 0$

$y - 6 = 0$

Step 3

Set $y - 10$ equal to $0$ and solve for $y$ .

Set $y - 10$ equal to $0$ .

$y - 10 = 0$

Add $10$ to both sides of the equation.

$y = 10$

Step 4

Set $y - 6$ equal to $0$ and solve for $y$ .

Set $y - 6$ equal to $0$ .

$y - 6 = 0$

Add $6$ to both sides of the equation.

$y = 6$

Step 5

The final solution is all the values that make $(y - 10) (y - 6) = 0$ true.

$y = 10, 6$

Solve by Factoring y^2-16y+60=0

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