Solve by Graphing 10x-2y=20 , 5x=y+10

$10 x - 2 y = 20$ , $5 x = y + 10$

Step 1

Subtract $10 x$ from both sides of the equation.

$- 2 y = 20 - 10 x$

$5 x = y + 10$

Step 2

Divide each term in $- 2 y = 20 - 10 x$ by $- 2$ and simplify.

Divide each term in $- 2 y = 20 - 10 x$ by $- 2$ .

$\frac{- 2 y}{- 2} = \frac{20}{- 2} + \frac{- 10 x}{- 2}$

$5 x = y + 10$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 y}{- 2} = \frac{20}{- 2} + \frac{- 10 x}{- 2}$

$5 x = y + 10$

Divide $y$ by $1$ .

$y = \frac{20}{- 2} + \frac{- 10 x}{- 2}$

$5 x = y + 10$

$y = \frac{20}{- 2} + \frac{- 10 x}{- 2}$

$5 x = y + 10$

$y = \frac{20}{- 2} + \frac{- 10 x}{- 2}$

$5 x = y + 10$

Simplify the right side.

Simplify each term.

Divide $20$ by $- 2$ .

$y = - 10 + \frac{- 10 x}{- 2}$

$5 x = y + 10$

Cancel the common factor of $- 10$ and $- 2$ .

Factor $- 2$ out of $- 10 x$ .

$y = - 10 + \frac{- 2 (5 x)}{- 2}$

$5 x = y + 10$

Cancel the common factors.

Factor $- 2$ out of $- 2$ .

$y = - 10 + \frac{- 2 (5 x)}{- 2 \cdot 1}$

$5 x = y + 10$

Cancel the common factor.

$y = - 10 + \frac{- 2 (5 x)}{- 2 \cdot 1}$

$5 x = y + 10$

Rewrite the expression.

$y = - 10 + \frac{5 x}{1}$

$5 x = y + 10$

Divide $5 x$ by $1$ .

$y = - 10 + 5 x$

$5 x = y + 10$

$y = - 10 + 5 x$

$5 x = y + 10$

$y = - 10 + 5 x$

$5 x = y + 10$

$y = - 10 + 5 x$

$5 x = y + 10$

$y = - 10 + 5 x$

$5 x = y + 10$

$y = - 10 + 5 x$

$5 x = y + 10$

Step 3

Rewrite the equation as $y + 10 = 5 x$ .

$y + 10 = 5 x$

$y = - 10 + 5 x$

Step 4

Subtract $10$ from both sides of the equation.

$y = 5 x - 10$

$y = - 10 + 5 x$

Step 5

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

Always true

Step 6

Solve by Graphing 10x-2y=20 , 5x=y+10

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