Solve by Graphing 12x-3y=24 4x=y+8

$12 x - 3 y = 24$ $4 x = y + 8$

Step 1

Subtract $12 x$ from both sides of the equation.

$- 3 y = 24 - 12 x$

$4 x = y + 8$

Step 2

Divide each term in $- 3 y = 24 - 12 x$ by $- 3$ and simplify.

Divide each term in $- 3 y = 24 - 12 x$ by $- 3$ .

$\frac{- 3 y}{- 3} = \frac{24}{- 3} + \frac{- 12 x}{- 3}$

$4 x = y + 8$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 y}{- 3} = \frac{24}{- 3} + \frac{- 12 x}{- 3}$

$4 x = y + 8$

Divide $y$ by $1$ .

$y = \frac{24}{- 3} + \frac{- 12 x}{- 3}$

$4 x = y + 8$

$y = \frac{24}{- 3} + \frac{- 12 x}{- 3}$

$4 x = y + 8$

$y = \frac{24}{- 3} + \frac{- 12 x}{- 3}$

$4 x = y + 8$

Simplify the right side.

Simplify each term.

Divide $24$ by $- 3$ .

$y = - 8 + \frac{- 12 x}{- 3}$

$4 x = y + 8$

Cancel the common factor of $- 12$ and $- 3$ .

Factor $- 3$ out of $- 12 x$ .

$y = - 8 + \frac{- 3 (4 x)}{- 3}$

$4 x = y + 8$

Cancel the common factors.

Factor $- 3$ out of $- 3$ .

$y = - 8 + \frac{- 3 (4 x)}{- 3 \cdot 1}$

$4 x = y + 8$

Cancel the common factor.

$y = - 8 + \frac{- 3 (4 x)}{- 3 \cdot 1}$

$4 x = y + 8$

Rewrite the expression.

$y = - 8 + \frac{4 x}{1}$

$4 x = y + 8$

Divide $4 x$ by $1$ .

$y = - 8 + 4 x$

$4 x = y + 8$

$y = - 8 + 4 x$

$4 x = y + 8$

$y = - 8 + 4 x$

$4 x = y + 8$

$y = - 8 + 4 x$

$4 x = y + 8$

$y = - 8 + 4 x$

$4 x = y + 8$

$y = - 8 + 4 x$

$4 x = y + 8$

Step 3

Rewrite the equation as $y + 8 = 4 x$ .

$y + 8 = 4 x$

$y = - 8 + 4 x$

Step 4

Subtract $8$ from both sides of the equation.

$y = 4 x - 8$

$y = - 8 + 4 x$

Step 5

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

Always true

Step 6

Solve by Graphing 12x-3y=24 4x=y+8

Related Questions

Support LCMGCF.com by disabling your adblocker.