Solve by Graphing 12x-3y=9 , y-4x=-3

$12 x - 3 y = 9$ , $y - 4 x = - 3$

Step 1

Subtract $12 x$ from both sides of the equation.

$- 3 y = 9 - 12 x$

$y - 4 x = - 3$

Step 2

Divide each term in $- 3 y = 9 - 12 x$ by $- 3$ and simplify.

Divide each term in $- 3 y = 9 - 12 x$ by $- 3$ .

$\frac{- 3 y}{- 3} = \frac{9}{- 3} + \frac{- 12 x}{- 3}$

$y - 4 x = - 3$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 y}{- 3} = \frac{9}{- 3} + \frac{- 12 x}{- 3}$

$y - 4 x = - 3$

Divide $y$ by $1$ .

$y = \frac{9}{- 3} + \frac{- 12 x}{- 3}$

$y - 4 x = - 3$

$y = \frac{9}{- 3} + \frac{- 12 x}{- 3}$

$y - 4 x = - 3$

$y = \frac{9}{- 3} + \frac{- 12 x}{- 3}$

$y - 4 x = - 3$

Simplify the right side.

Simplify each term.

Divide $9$ by $- 3$ .

$y = - 3 + \frac{- 12 x}{- 3}$

$y - 4 x = - 3$

Cancel the common factor of $- 12$ and $- 3$ .

Factor $- 3$ out of $- 12 x$ .

$y = - 3 + \frac{- 3 (4 x)}{- 3}$

$y - 4 x = - 3$

Cancel the common factors.

Factor $- 3$ out of $- 3$ .

$y = - 3 + \frac{- 3 (4 x)}{- 3 \cdot 1}$

$y - 4 x = - 3$

Cancel the common factor.

$y = - 3 + \frac{- 3 (4 x)}{- 3 \cdot 1}$

$y - 4 x = - 3$

Rewrite the expression.

$y = - 3 + \frac{4 x}{1}$

$y - 4 x = - 3$

Divide $4 x$ by $1$ .

$y = - 3 + 4 x$

$y - 4 x = - 3$

$y = - 3 + 4 x$

$y - 4 x = - 3$

$y = - 3 + 4 x$

$y - 4 x = - 3$

$y = - 3 + 4 x$

$y - 4 x = - 3$

$y = - 3 + 4 x$

$y - 4 x = - 3$

$y = - 3 + 4 x$

$y - 4 x = - 3$

Step 3

Add $4 x$ to both sides of the equation.

$y = - 3 + 4 x$

Step 4

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$y = 4 x - 3$

Step 5

Solve by Graphing 12x-3y=9 , y-4x=-3

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