Solve by Graphing 16x-4y=32 , 4x=y+8

$16 x - 4 y = 32$ , $4 x = y + 8$

Step 1

Subtract $16 x$ from both sides of the equation.

$- 4 y = 32 - 16 x$

$4 x = y + 8$

Step 2

Divide each term in $- 4 y = 32 - 16 x$ by $- 4$ and simplify.

Divide each term in $- 4 y = 32 - 16 x$ by $- 4$ .

$\frac{- 4 y}{- 4} = \frac{32}{- 4} + \frac{- 16 x}{- 4}$

$4 x = y + 8$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 y}{- 4} = \frac{32}{- 4} + \frac{- 16 x}{- 4}$

$4 x = y + 8$

Divide $y$ by $1$ .

$y = \frac{32}{- 4} + \frac{- 16 x}{- 4}$

$4 x = y + 8$

$y = \frac{32}{- 4} + \frac{- 16 x}{- 4}$

$4 x = y + 8$

$y = \frac{32}{- 4} + \frac{- 16 x}{- 4}$

$4 x = y + 8$

Simplify the right side.

Simplify each term.

Divide $32$ by $- 4$ .

$y = - 8 + \frac{- 16 x}{- 4}$

$4 x = y + 8$

Cancel the common factor of $- 16$ and $- 4$ .

Factor $- 4$ out of $- 16 x$ .

$y = - 8 + \frac{- 4 (4 x)}{- 4}$

$4 x = y + 8$

Cancel the common factors.

Factor $- 4$ out of $- 4$ .

$y = - 8 + \frac{- 4 (4 x)}{- 4 \cdot 1}$

$4 x = y + 8$

Cancel the common factor.

$y = - 8 + \frac{- 4 (4 x)}{- 4 \cdot 1}$

$4 x = y + 8$

Rewrite the expression.

$y = - 8 + \frac{4 x}{1}$

$4 x = y + 8$

Divide $4 x$ by $1$ .

$y = - 8 + 4 x$

$4 x = y + 8$

$y = - 8 + 4 x$

$4 x = y + 8$

$y = - 8 + 4 x$

$4 x = y + 8$

$y = - 8 + 4 x$

$4 x = y + 8$

$y = - 8 + 4 x$

$4 x = y + 8$

$y = - 8 + 4 x$

$4 x = y + 8$

Step 3

Rewrite the equation as $y + 8 = 4 x$ .

$y + 8 = 4 x$

$y = - 8 + 4 x$

Step 4

Subtract $8$ from both sides of the equation.

$y = 4 x - 8$

$y = - 8 + 4 x$

Step 5

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

Always true

Step 6

Solve by Graphing 16x-4y=32 , 4x=y+8

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