Solve by Graphing 20x-4y=40 , 5x=y+10

$20 x - 4 y = 40$ , $5 x = y + 10$

Step 1

Subtract $20 x$ from both sides of the equation.

$- 4 y = 40 - 20 x$

$5 x = y + 10$

Step 2

Divide each term in $- 4 y = 40 - 20 x$ by $- 4$ and simplify.

Divide each term in $- 4 y = 40 - 20 x$ by $- 4$ .

$\frac{- 4 y}{- 4} = \frac{40}{- 4} + \frac{- 20 x}{- 4}$

$5 x = y + 10$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 y}{- 4} = \frac{40}{- 4} + \frac{- 20 x}{- 4}$

$5 x = y + 10$

Divide $y$ by $1$ .

$y = \frac{40}{- 4} + \frac{- 20 x}{- 4}$

$5 x = y + 10$

$y = \frac{40}{- 4} + \frac{- 20 x}{- 4}$

$5 x = y + 10$

$y = \frac{40}{- 4} + \frac{- 20 x}{- 4}$

$5 x = y + 10$

Simplify the right side.

Simplify each term.

Divide $40$ by $- 4$ .

$y = - 10 + \frac{- 20 x}{- 4}$

$5 x = y + 10$

Cancel the common factor of $- 20$ and $- 4$ .

Factor $- 4$ out of $- 20 x$ .

$y = - 10 + \frac{- 4 (5 x)}{- 4}$

$5 x = y + 10$

Cancel the common factors.

Factor $- 4$ out of $- 4$ .

$y = - 10 + \frac{- 4 (5 x)}{- 4 \cdot 1}$

$5 x = y + 10$

Cancel the common factor.

$y = - 10 + \frac{- 4 (5 x)}{- 4 \cdot 1}$

$5 x = y + 10$

Rewrite the expression.

$y = - 10 + \frac{5 x}{1}$

$5 x = y + 10$

Divide $5 x$ by $1$ .

$y = - 10 + 5 x$

$5 x = y + 10$

$y = - 10 + 5 x$

$5 x = y + 10$

$y = - 10 + 5 x$

$5 x = y + 10$

$y = - 10 + 5 x$

$5 x = y + 10$

$y = - 10 + 5 x$

$5 x = y + 10$

$y = - 10 + 5 x$

$5 x = y + 10$

Step 3

Rewrite the equation as $y + 10 = 5 x$ .

$y + 10 = 5 x$

$y = - 10 + 5 x$

Step 4

Subtract $10$ from both sides of the equation.

$y = 5 x - 10$

$y = - 10 + 5 x$

Step 5

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

Always true

Step 6

Solve by Graphing 20x-4y=40 , 5x=y+10

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