Solve by Graphing 2x-3y=-1 y=x-1

$2 x - 3 y = - 1$ $y = x - 1$

Step 1

Subtract $2 x$ from both sides of the equation.

$- 3 y = - 1 - 2 x$

$y = x - 1$

Step 2

Divide each term in $- 3 y = - 1 - 2 x$ by $- 3$ and simplify.

Divide each term in $- 3 y = - 1 - 2 x$ by $- 3$ .

$\frac{- 3 y}{- 3} = \frac{- 1}{- 3} + \frac{- 2 x}{- 3}$

$y = x - 1$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 y}{- 3} = \frac{- 1}{- 3} + \frac{- 2 x}{- 3}$

$y = x - 1$

Divide $y$ by $1$ .

$y = \frac{- 1}{- 3} + \frac{- 2 x}{- 3}$

$y = x - 1$

$y = \frac{- 1}{- 3} + \frac{- 2 x}{- 3}$

$y = x - 1$

$y = \frac{- 1}{- 3} + \frac{- 2 x}{- 3}$

$y = x - 1$

Simplify the right side.

Simplify each term.

Dividing two negative values results in a positive value.

$y = \frac{1}{3} + \frac{- 2 x}{- 3}$

$y = x - 1$

Dividing two negative values results in a positive value.

$y = \frac{1}{3} + \frac{2 x}{3}$

$y = x - 1$

$y = \frac{1}{3} + \frac{2 x}{3}$

$y = x - 1$

$y = \frac{1}{3} + \frac{2 x}{3}$

$y = x - 1$

$y = \frac{1}{3} + \frac{2 x}{3}$

$y = x - 1$

Step 3

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(4, 3)$

Step 4