Solve by Graphing 2x-4y=-8 , y=-3x+2

$2 x - 4 y = - 8$ , $y = - 3 x + 2$

Step 1

Subtract $2 x$ from both sides of the equation.

$- 4 y = - 8 - 2 x$

$y = - 3 x + 2$

Step 2

Divide each term in $- 4 y = - 8 - 2 x$ by $- 4$ and simplify.

Divide each term in $- 4 y = - 8 - 2 x$ by $- 4$ .

$\frac{- 4 y}{- 4} = \frac{- 8}{- 4} + \frac{- 2 x}{- 4}$

$y = - 3 x + 2$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 y}{- 4} = \frac{- 8}{- 4} + \frac{- 2 x}{- 4}$

$y = - 3 x + 2$

Divide $y$ by $1$ .

$y = \frac{- 8}{- 4} + \frac{- 2 x}{- 4}$

$y = - 3 x + 2$

$y = \frac{- 8}{- 4} + \frac{- 2 x}{- 4}$

$y = - 3 x + 2$

$y = \frac{- 8}{- 4} + \frac{- 2 x}{- 4}$

$y = - 3 x + 2$

Simplify the right side.

Simplify each term.

Divide $- 8$ by $- 4$ .

$y = 2 + \frac{- 2 x}{- 4}$

$y = - 3 x + 2$

Cancel the common factor of $- 2$ and $- 4$ .

Factor $- 2$ out of $- 2 x$ .

$y = 2 + \frac{- 2 x}{- 4}$

$y = - 3 x + 2$

Cancel the common factors.

Factor $- 2$ out of $- 4$ .

$y = 2 + \frac{- 2 x}{- 2 \cdot 2}$

$y = - 3 x + 2$

Cancel the common factor.

$y = 2 + \frac{- 2 x}{- 2 \cdot 2}$

$y = - 3 x + 2$

Rewrite the expression.

$y = 2 + \frac{x}{2}$

$y = - 3 x + 2$

$y = 2 + \frac{x}{2}$

$y = - 3 x + 2$

$y = 2 + \frac{x}{2}$

$y = - 3 x + 2$

$y = 2 + \frac{x}{2}$

$y = - 3 x + 2$

$y = 2 + \frac{x}{2}$

$y = - 3 x + 2$

$y = 2 + \frac{x}{2}$

$y = - 3 x + 2$

Step 3

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(0, 2)$

Step 4

Solve by Graphing 2x-4y=-8 , y=-3x+2

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